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Ad libitum [116K]
3 years ago
6

10. The Johnson family purchased a new television that had a 62 inch diagonal. The height of the television was 30 inches. Appro

ximately how wide is the new television? show work​
Mathematics
1 answer:
lana66690 [7]3 years ago
7 0

Answer:

Width = 54.3 inches

Step-by-step explanation:

We solve this question using the Pythagoras Theorem

Width² + Height² = Diagonal²

From the above question

Width= ??

Height = 30 inches

Diagonal = 62 inches

Width² + 30² = 62²

Width² = 62² - 30²

Width = √62² - 30²

Width =✓2944

Width = 54.258639865 inches

Approximately

Width = 54.3 inches

Hence, the new television was 54.3 inches wide.

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(7,-8)(-4,6)
slope = 6 - (-8) / (-4 - 7) = (6 + 8) / -11 = -14/11

point slope : y - y1= m(x - x1)
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A student is conducting a probability experiment and wants to know the total number of outcomes for the experiment. The student'
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Answer:So to get a 6 when rolling a six-sided die, probability = 1 ÷ 6 = 0.167, or 16.7 percent chance. So to get two 6s when rolling two dice, probability = 1/6 × 1/6 = 1/36 = 1 ÷ 36 = 0.0278, or 2.78 percent.

Step-by-step explanation:

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you want to create a 99 confidence interval with a margin of error of 25 assuming that the population standard deviation is equa
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Answer:

The minimum sample size is 239.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.99}{2} = 0.005

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.005 = 0.995, so Z = 2.575.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

Population standard deviation is equal to 1.5

This means that \sigma = 1.5

Margin of error of 0.25

This means that M = 0.25

What's the minimum size of the sample?

M = z\frac{\sigma}{\sqrt{n}}

0.25 = 2.575\frac{1.5}{\sqrt{n}}

0.25\sqrt{n} = 2.575*1.5

\sqrt{n} = \frac{2.575*1.5}{0.25}

(\sqrt{n})^2 = (\frac{2.575*1.5}{0.25})^2

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Rounding up:

The minimum sample size is 239.

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