The price of one pound of banana = b
As one pound of oranges costs $0.75 more than one pound of bananas, so, the price of one pound of orange = b+0.75.
The price of 3 pounds of banana = 3b,
and the price of 2 pounds of oranges = 2(b+0.75).
Now, as she pays $4.50 for 3 pounds of bananas and 2 pounds of oranges.
So, for this situation the required equation is
3b + 2(b+0.75) =4.5
On solving this equation, we have
Hence, the price of one pound of banana = $ 0.60
and the price of one pound of orange
=b+0.75= 0.60+0.75=$1.35.
Complete Question:
Each night you total the day's sales and the total volume of ice cream sold in your shop. You notice that when an employee named Ben works, the mean price of the ice cream sold is $2.30 per pint with a standard deviation of $0.05. On nights when an employee named Jerry works, the mean price of the ice cream sold is $2.25 per pint with a standard deviation of $0.35. Which employee likely receives more complaints that his servings are too small? Explain.
Answer:
The employee that likely receives more complaints that his servings are too small is Jerry.
Step-by-step explanation:
a) Data:
Ben's mean price of ice cream sold = $2.30 per pint
Ben's mean price has a standard deviation = $0.05 (2.2%)
Jerry's mean price of ice cream sold = $2.25 per pint
Jerry's mean price has a standard deviation = $0.35 (15.5%)
b) Whereas the mean price of Ben's ice cream is $2.30, Jerry's mean price is less by $0.05, more than 20%. On the other hand, the standard deviation of Ben's mean price is $0.05 (about 2.2% variation), while Jerry's is $0.35 representing about 15.6% variation. This means that the variations in Jerry's price are far too much when compared to Ben's.
c) Percentages of Variations:
Ben = $0.05/$2.30 * 100 = 2.2%
Jerry = $0.35/$2.25 * 100 = 15.6%
Answer:
252m^2
Step-by-step explanation:
The formula for surface area of a rectangular prism is 2(hl)+2(hw)+2(wl).
we just plug in the values.
2(12 x 6) + 2(12 x 3) + 2(6 x 3)
= 2(72) + 2(36) + 2(18) then simplify
= 144 + 72 + 36
= 252
Answer:
shows correct substitution of the values a, b, and c from the given quadratic equation into quadratic formula.
Step-by-step explanation:
Given: The quadratic equation
We have to show the correct substitution of the values a, b, and c from the given quadratic equation into quadratic formula.
The standard form of quadratic equation is then the solution of quadratic equation using quadratic formula is given as
Consider the given quadratic equation
Comparing with general quadratic equation, we have
a = -3 , b = -2 , c = 6
Substitute in quadratic formula, we get,
Simplify, we have,
Thus, and x_{2}=\frac{2-\sqrt{76} }{-6}
Simplify, we get,
Thus, shows correct substitution of the values a, b, and c from the given quadratic equation into quadratic formula.
Here is the graph of x-y=4. According to this, the x intercept is (4,0), and the y intercept is (0,-4) :)
