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nikklg [1K]
3 years ago
15

Which shape has a larger atea a rectangle that is 7 inches by 3/4 inch, or a square with side length of 2 1/2 inches?

Mathematics
1 answer:
viktelen [127]3 years ago
8 0
The square has a larger area
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how would you arrange four 3's so they equal the number 0 through 10? I did 0 and 1 need help with the other numbers PLEASES!!!
Harlamova29_29 [7]
3+3+3-3=6

(3+3+3-3)÷2=3

(3+3+3+3)÷3=4

(3+3+3+3)÷6=2

Is this how it works?
5 0
3 years ago
What is the probability of not drawing a card 6 or greater from a regular deck of cards?
Mamont248 [21]
Ok so there are 52 cards in a deck if you take all the cards that have the number 6 which is only 4 cards so 52-4 = 48 cards without any 6 so the ratio is 48/52 
chances.

If you're trying to take any card that is greater than 6 its a little more complex there is T,2,3,4,5,6,7,8,9,10,B,Q,K so you have to tack away 6,7,8,9,10,B,Q,K from 4 rows so 8 x 4 =32 cards 52-32= 20 so the probability of not having any cards greater than 6 is 20/52
3 0
3 years ago
The school is planing a file trip they have 81 busses .each bus has 62 seats how many students can go
Tresset [83]

Answer:

5,022 Students

Step-by-step explanation:

All you have to do it multiply!

Like so:

81*62= 5,022

4 0
3 years ago
The distance between two points on a number line can be found by taking the ____A_____ of the ____B_____ of the coordinates. Fil
xeze [42]

Answer:

The distance between two points on a number line can be found by taking the <u>absolute value</u> of the <u>difference</u> of the coordinates.

Step-by-step explanation:

  • Every point can be paired with a number on a number line
  • The coordinate is the number associated with a point
  • To find the distance between point A and B you subtract the coordinates in any order you like and take the absolute value.
6 0
3 years ago
Simplify this expression
pishuonlain [190]

Answer:

After simplifying, the exponent of x is 33 and the exponent of y is 0

Step-by-step explanation:

For us to simplify, we bring the x base together and the y base together

Recall from the law of indices;

x^a/x^b = x^(a-b)

and x^a * x^b = x^(a + b)

We shall be applying these here

Let us bring the x terms together

we have these as;

x^8/x^14 * 1/x^-39 = x^( 8 - 14 -(-39))

= x^(8 + 39-14) = x^33

for y, we have it that;

y^-26/y^-5 * 1/y^-21

= y^(-26 -(-5) - (-21)

= y^-26 + 5 + 21 = y^0

8 0
3 years ago
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