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kakasveta [241]
4 years ago
10

What does 500+38+2538+48 equal​

Mathematics
2 answers:
gogolik [260]4 years ago
8 0
500+38=538+2538=3076+48=
My answer would be 3124 or 3,124
Aliun [14]4 years ago
5 0
The answer is: 3,124
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Tyler's mom purchased a savings bond for Tyler. The value of the savings bond increases by 4% each year. One year after it was p
Gemiola [76]

Answer:

The value of the bond when Tyler's mom purchased it was $150

Step-by-step explanation:

we know that

In this problem we have a exponential function of the form

f(x)=a(b)^{x}

where

a is the initial value (y-intercept)

b is the base

r is the rate

b=(1+r)

In this problem

r=4%=4/100=0.04

b=1+0.04=1.04

substitute

f(x)=a(1.04)^{x}

where

x is the number of years since the savings bond was purchased

f(x) is the value of the savings bond

For x=1

f(x)=$156

substitute

156=a(1.04)^{1}

Solve for a

156=a(1.04)

a=\$150

therefore

The value of the bond when Tyler's mom purchased it was $150

8 0
4 years ago
after buying a burger thet cost $5 roy had no more then $23 in his pocket how much money did roy have before buying the burger
viktelen [127]
He has 28 dollars now
3 0
4 years ago
A compound of two chemicals is mixed in a ratio of 3:12 if there are 45L of the compound how much of each chemical is in the mix
zzz [600]

3x+12x=45

15x=45

x=3

the first chemical is 3*3 or 9 L

the second chemical is 12*3 = 36 L

6 0
4 years ago
Read 2 more answers
I need help btw i am in middle school
Tju [1.3M]
I think the answer is 11
6 0
3 years ago
The population of a rabbit colony triples every 3 days. The population starts at 10 rabbits. Write an exponential function that
qaws [65]

Answer:

Step-by-step explanation:

The population at various days is as follows since population triples every 3 days

<u>Day</u>     <u>Population</u>

0          10

3          30

6          90

9          270

....         ......

This can be modeled by the general equation

n_{t} = n_{0}(r)^{t/k}

where

n_{t} is the population after t days

n_{0} is the population at start (10)

r is the rate at which population changes ie 3

t is the number days from start

k is the number of days at which the population triples(here k =3 days)

We can check this by plugging in values for each of the variables

At day 0, population = 10(3)⁰ = 10. 1 = 10

Similarly populations for days 3, 6, 9 are:

\\\\10.3^{3/3} = 10. 3^1 = 10.3 = 30\\10.3^{6/3} = 10. 3^2 = 10.9 = 90\\\\10.3^{9/3} = 10. 3^3 = 10.27 = 270

8 0
1 year ago
Read 2 more answers
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