The value of y varies directly with x and y=12 when x=-6 find y when x=-4

Mathematics

1 answer:

FinnZ [79.3K]3 years ago

8 0

Answer:

B)8

Step-by-step explanation:

That is the right answer because when y=12, x=-6

12/-6 = -2

This means that x = y/-2

or y = x * -2

-4 * -2 = 8

Hope I helped

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which of the following best describes the technique used to graph the equation using the slope and y-intercept ? Y=5x+10

Vinvika [58]

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3 years ago

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A projectile is launched from the ground at an angle of theta above the horizontal with an initial speed of v in ft/s. The rang

VARVARA [1.3K]

Answer:

$\theta=24.4^\circ$

Step-by-step explanation:

The formula you wrote has the fraction the other way around. You can find that the range of a projectile is in reality approximated by the equation $x=\frac{v^2}{g} sin(2\theta)=\frac{v^2}{32ft/s^2} sin(2\theta)$ , where we will use ft for distances.

From the given equation we have then $\frac{x32ft/s^2}{v^2} =sin(2\theta)$ , which means $\theta=\frac{Arcsin(\frac{x32ft/s^2}{v^2})}{2}$ since the arcsin is the inverse function of the sin.

Since we have x = 170 ft and v = 85 ft/s, we can substitute these values from the equation written, and we will have $\theta=\frac{Arcsin(\frac{(170ft)(32ft/s^2)}{(85ft/s)^2})}{2}$ , and from now on we have just to use a calculator, obtaining $\theta=\frac{Arcsin(0.75294117647)}{2}=\frac{48.84579804^\circ}{2}=24.4^\circ$