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3 years ago

Which statement is true about CR and DS?

Mathematics

1 answer:

frosja888 [35]3 years ago

3 0

Answer:

It is given that, AB and P Q are parallel lines.Line segment CR and D S, intersect the two lines.

Line segment CR and D S ,are Transversal to parallel lines, AB and P Q.

⇒∠C + ∠ R=180°

⇒90°+∠ R=180°

∠ R=180°-90°

∠R=90°

Similarly, ∠S=90°

→∠R+∠S=90°+90°=180°

As, sum of interior angles on the same side of transversal is 180°, so lines are Parallel.

→CR║DS

Also, AB║CD→CD║RS.

If in a Quadrilateral, opposite sides are parallel, then it is a Parallelogram,and also each interior angle has measure 90°, so it is a Rectangle.

In a rectangle opposite sides are equal.

Step-by-step explanation:

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a motorboat moves across a lake as a constant speed. when it begins, it is 50 km from the shore. after 9 minutes, it is 14 km fr

nikdorinn [45]

Answer:

The function describes the motorboat's distance from the shore $y=-4x+50$

Step-by-step explanation:

A motorboat moves across a lake as a constant speed. when it begins, it is 50 km from the shore

After 9 minutes, it is 14 km from the shore.

So, rate of change = $\frac{\text{Final distance}-\text{Initial distance}}{time}=\frac{14-50}{9}=-4$

Negative sign shows that there is decrease in distance per minute

The rate of change of distance is 4 km / minutes

General equation : y = mx+c

Where m is the slope and c is the constant

Substitute the values in the equation :

y=-4x+50

Where y is the final distance and x is the minutes

So, Option C is true

Hence The function describes the motorboat's distance from the shore $y=-4x+50$

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3 years ago

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Black_prince [1.1K]

Answer:

Step-by-step explanation:

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To mix plaster for a dental model, 35 mL of water is used for 100g of plaster. How many mL of water should be used for 250g of p

laila [671]

Okay, here we have this:

Considering the provided information, we are going to calculate the requested value, so we obtain the following rule of three:

$\begin{gathered} \frac{x}{35mL\text{ of water}}=\frac{250g\text{ of plaster}}{100g\text{ of plaster}} \\ x=\frac{250g\text{ of plaster}}{100g\text{ of plaster}}\cdot35mL\text{ of water} \end{gathered}$

Solving for x:

$\begin{gathered} x=2.5\cdot35mL\text{ of water} \\ x=87.5mL\text{ of water} \end{gathered}$

Finally we obtain that 87.5mL of water should be used for 250g of plaster.

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1 year ago