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Anika [276]
3 years ago
11

Each of the walls of a room with square dimensions has been built with two pieces of sheetrock, a smaller one and a larger one.

the length of all the smaller ones is the same and is stored in the variable small. similarly, the length of all the larger ones is the same and is stored in the variable large. write a single expression whose value is the total area of this room. do not use the pow function. submit
Mathematics
1 answer:
azamat3 years ago
8 0
To solve this problem you must apply the proccedure shown below:

 1. You have the following information given in the problem above:

 -  The<span> room has square dimensions and it has been built with two pieces of sheetrock, a smaller one and a larger one.

 2. Therefore, let's call

 x: the smaller one.
 y: the larger one.

 3. Then, you have that the lenght of the wall is the sum of the smaller one and the larger one:

 x+y

 4. So, the area of the room is:

 (x+y)(x+y)
 (x+y)</span>²

 Therefore, the answer is: (x+y)²
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Answer:

Area = 27 cm²

Step-by-step explanation:

let L be the length of the rectangle

    w the width

    P the perimeter

    A the area

<u>Formulas</u> :

P = 2×(L + w)

A = L × w

<u>We are Given</u> :

L = 3w

P = 2×(L + w)

⇔ 24 = 2×(3w + w)

⇔ 24 = 2×4w

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⇔ w = 24/8 = 3

Then

L = 3w = 3×3 = 9

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Then

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Answer:

Here you go, hope this helps

Step-by-step explanation:

Exact form: 13/12

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3 0
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vova2212 [387]
Plug in (4,64) into each answer choice.

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Answer choice A is correct.

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Answer choice B is incorrect.

C) f(x) = 4(2)^{-x}
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Answer choice C is incorrect.

D) f(x) = 2(4)^{-x}
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Answer choice D is incorrect.


Your answer is B<span>) f(x)=2(4)^x</span>
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