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Wittaler [7]
3 years ago
12

plz help me now plz: A cable 65 meters long is cut into two pieces so that one piece is 18 meters longer than the other. Find th

e length of each piece of cable
Mathematics
1 answer:
GalinKa [24]3 years ago
6 0

Answer:

One piece is 23.5

the other is 41.5

Step-by-step explanation:

first subtract 18 from 65 that will give you 47. Then 47÷2= 23.5. this is the length of the shorter piece. since one piece is 18 m longer then the other, add 18 to 23.5. that will give you the length of the longer piece. You can check your work by adding 23.5 and 41.5. They equal 65.

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1
kirza4 [7]
Each game was $44.99, if she spent a total of 284.97 and we subtract the cost of the console 284.97 - 194.99 = 89.98, since the two games were equally priced we divide 89.98/2 and get $44.98
8 0
3 years ago
Convert 3<br> 8 into a decimal.
marishachu [46]

Answer:

0.375

Step-by-step explanation:

3/8=0.375, use a calculator for this or long division

7 0
3 years ago
What is the following quotient? 6-3(3 √8)/3 √9
WARRIOR [948]

Answer:

Factor the numerator and denominator and cancel the common factors.

Exact Form:

2

3

√

3

−

3

√

18

Decimal Form:

0.26375774

5 0
3 years ago
Read 2 more answers
there are 6 elementary schools in district. each school has 412 students. how many students in all are in the district? Solve th
kiruha [24]

Answer:

2472 students

Step-by-step explanation:

<u>What we know:</u>

- There are 6 schools

- Each school has 412 students

<u>What we're trying to solve:</u>

How many students are there altogether?

To find this, we multiply 412 by 6. Doing this is essentially the same as adding 412 to itself 6 times for each school there is in the district.

412 students × 6 schools

= 2472 students

Therefore, there are 2472 students in the district.

I hope this helps!

3 0
3 years ago
There are five nickels, five dimes and five quarters in your pocket. You randomly pick three coins and place them on the counter
Goshia [24]

Answer:

The question is incomplete, this is the complete question.;

There are five nickels, five dimes and five quarters in your pocket. You randomly pick three coins and place them on the counter the first coin is a nickel, the second is a dime and the third is a quarter.find the probability of this occurring.

The answer to the question is;

the probability of this occurring is 1/27

Step-by-step explanation:

Let n(N) =5 ( the number of nickels)

n(D) =5 ( the number of dimes) and

n(Q) = 5 ( the number of quarters)

P(N)= 5/15=1/3 (prob of picking a nickel)

P(D) =5/15=1/3 (prob of picking a dime)

P(Q) = 5/15= 1/3 (prob of picking a quatre)

The probability of picking the three= P(N)×P(D)×P(Q)

= 1/3×1/3×1/3

= 1/27

7 0
4 years ago
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