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3 years ago

Describe the relationship between the two quantities. Volume of a cylinder; Height & radius of cylinder's base.

Mathematics

2 answers:

seropon [69]3 years ago

5 0

Answer:

The Volume is directly proportional to the radius in the Base Area and the height of a Cylinder

Step-by-step explanation:

Well, every time you check it out the Volume of Cylinder

$V=\pi r^{2}h$

You can view it as:

Base Area times the height

Base Area= \pi r^{2} Circle Area

Height =h

So the Volume is directly proportional to the radius in the Base Area and the height of a Cylinder. The higher the cylinder, the more volume it will be able to take. The larger the base (bigger the radius) the greater capacity it will take.

oee [108]3 years ago

4 0

Answer:

V = pi r^2 h

Step-by-step explanation:

Volume = the constant pi times the square of radius of the base * height

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Let X be a Bernoulli rv with pmf as in Example 3.18. a. Compute E(X2 ). b. Show that V(X) 5 p(1 2 p). c. Compute E(X79).

spayn [35]

The Bernoulli distribution is a distribution whose random variable can only take 0 or 1

The value of E(x2) is p
The value of V(x) is p(1 - p)
The value of E(x79) is p

<h3>How to compute E(x2)</h3>

The distribution is given as:

p(0) = 1 - p

p(1) = p

The expected value of x2, E(x2) is calculated as:

$E(x^2) = \sum x^2 * P(x)$

So, we have:

$E(x^2) = 0^2 * (1- p) + 1^2 * p$

Evaluate the exponents

$E(x^2) = 0 * (1- p) + 1 * p$

Multiply

$E(x^2) = 0 +p$

Add

$E(x^2) = p$

Hence, the value of E(x2) is p

<h3>How to compute V(x)</h3>

This is calculated as:

$V(x) = E(x^2) - (E(x))^2$

Start by calculating E(x) using:

$E(x) = \sum x * P(x)$

So, we have:

$E(x) = 0 * (1- p) + 1 * p$

$E(x) = p$

Recall that:

$V(x) = E(x^2) - (E(x))^2$

So, we have:

$V(x) = p - p^2$

Factor out p

$V(x) = p(1 - p)$

Hence, the value of V(x) is p(1 - p)

<h3>How to compute E(x79)</h3>

The expected value of x79, E(x79) is calculated as:

$E(x^{79}) = \sum x^{79} * P(x)$

So, we have:

$E(x^{79}) = 0^{79} * (1- p) + 1^{79} * p$

Evaluate the exponents

$E(x^{79}) = 0 * (1- p) + 1 * p$

Multiply

$E(x^{79}) = 0 + p$

Add

$E(x^{79}) = p$

Hence, the value of E(x79) is p

Read more about probability distribution at:

brainly.com/question/15246027

5 0

3 years ago

The plot shown below displays the number of books

zheka24 [161]

Answer:

D has the most amount of people who haven't even read at all

Step-by-step explanation:

8 0

3 years ago

Three hundred ninety six divided by twenty four

Lunna [17]

Three hundred ninety six divided by twenty four = 16.5

5 0

3 years ago

Please Help !! Show All Work !!

GrogVix [38]

Answer:

1) (4,4) 2) (4,0) 3) (6,1)

Step-by-step explanation:

$(\frac{5+13}{2} )(\frac{7+1}{2} )\\(\frac{8}{2} )(\frac{8}{2} )\\(4,4)$

$(\frac{-3+7}{2} )(\frac{-3+3}{2} )\\(\frac{4}{2} )(\frac{0}{2} )\\(4,0)$

$\frac{-5+x_2}{2} =1$ multiply 1 by 2=2 then write $(+5)-5+x_2=1(+5)\\x_2 = 6$

$\frac{3+y_2}{2} =2$ multiply 2 by 2= 4 then write $(-3)3+y_2=4(-3)\\y_2=1$

4 0

3 years ago

If Quadrilateral Q is a scaled copy of Quadrilateral P created with a scale factor of 3

Stolb23 [73]

I don't see a drawing of the quadrilaterals, so I don't know what the perimeter of quadrilateral P is. But whatever the perimeter of P is, Q will be 1/3 of that. Perimeter is a length, so even though it may pertain to a 2-dimensional object, it is still a 1-dimensional, linear measure. When two objects are similar (same shape, but scaled up or down by a scale factor), all corresponding linear measures have the same scale factor.

If you were asked about area or volume, that would be a different matter. In the case of area, you would square the scale factor, and in the case of volume, you would cube the scale factor.

7 0

3 years ago