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zheka24 [161]
3 years ago
15

What is the volume of a cylinder with a radius of 5 cm and height of 10 cm? In terms of pi.

Mathematics
1 answer:
natka813 [3]3 years ago
5 0

Answer:

Volume of the cylinder=250π cm³

Step-by-step explanation:

The formula for calculating the volume of the cylinder is;

V=πr²h

where;

V=volume of the cylinder

π=pi

r=radius of the cylinder

h=height of the cylinder

In our case;

V=unknown

π

r=5 cm

h=10 cm

replacing;

V=π×5²×10=250π cm³

Volume of the cylinder=250π cm³

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Two buildings are 12m apart on the same horizontal level. From the top of the taller building, the angle of depression of the bo
Ksenya-84 [330]

Answer:

4.61 m

Step-by-step explanation:

The angle of depression of the bottom of the shorter building from the top of the taller building = 48° equals the angle of elevation of the top of the taller building from the bottom of the shorter building

Using trig ratios

tan48° = H/d where H = height of taller building and d = their distance apart = 12 m

H = dtan48° = 12tan48° = 13.33 m

Also, the angle of elevation of the top of the shorter building from the bottom of the taller building is 36°

Using trig ratios

tan36° = h/d where h = height of shorter building

h =dtan36° = 12tan36° = 8.72 m

Now, the difference in height of the buildings is thus H - h = 13.33 m - 8.72 m = 4.61 m

4 0
4 years ago
Let b be a number such that (2b+5)(b-1)=6b. What is the largest possible value of b? Express your answer as a common fraction.
Oksi-84 [34.3K]

Answer:

Foil the expression and solve the derivative with respect to b at f'(x)=02b^2+3b+5=6b\\d/dx(2b^2+9b+5=0)\\4b+9=0\\b=-9/4

Step-by-step explanation:

4 0
3 years ago
The isosceles triangles below are similar.
ohaa [14]

Answer: a) 2:1. b) 3. c) Perimeter of ΔEFG=36 Perimeter of ΔHIJ=18. d) 2:1

Step-by-step explanation:

a) Find the ratio of GF and JI. 16:8. Simplify by dividing both by 8 to get 2:1.

b) Set up this equation: 6/16=x/8. Cross-multiply. 6*8=48. Divide by 16. 48/16=3.

c) First find the length of one half of GF by dividing 16 by 2. 16/2=8. Set up the Pythagorean theorem. 8^2+6^2=c^2. Square 8 and 6. 64+36=c^2. Add 64 and 36. 100=c^2. Find the square root of 100. c=10.

EF and EG both measure 10 since they are shown to be congruent. 10+10+16=36.

Next find the length of one half of JI by dividing 8 by 2. 8/2=4. Set up the Pythagorean theorem. Since we know x=3, it will be 4^2+3^2=c^2. Square both 4 and 3. 16+9=c^2. Add 16 and 9. 25=c^2. Find the square root of 25. c=5.

HJ and HI both measure 5 since they are congruent. 5+5+8=18.

d) Find the ratio of the perimeters of ΔEFG and ΔHIJ. 36:18. Simplify by dividing both by 6 to get 6:3. Simplify further by dividing both by 3 to get 2:1.

4 0
3 years ago
3. ** Over the course of July, the high temperatures of 6 random days were collected. The data is 2 shown below. 84°F 92°F 79°F
Tresset [83]

Given data:

The given table.

The expression for the average temperature is,

\begin{gathered} 86^{\circ}F=\frac{84^{\circ}F+92^{\circ}F+79^{\circ}F+x+82^{\circ}F+93^{\circ}F}{6} \\ 516^{\circ}F=430^{\circ}F+x \\ x=86^{\circ}F \end{gathered}

Thus, the value of x is 86 degree Fahrenheit.

7 0
1 year ago
What is the factored form of 64g^3+8
vivado [14]
\bf \textit{difference and sum of cubes}
\\\\
a^3+b^3 = (a+b)(a^2-ab+b^2)\qquad
(a+b)(a^2-ab+b^2)= a^3+b^3 
\\\\
a^3-b^3 = (a-b)(a^2+ab+b^2)\qquad
(a-b)(a^2+ab+b^2)= a^3-b^3\\\\
-------------------------------\\\\
64g^3+8\implies 4^3g^3+8\implies (4g)^3+2^3
\\\\\\
(4g+2)[(4g)^2-(4g)(2)+2^2]\implies (4g+2)[(4^2g^2)-8g+4]
\\\\\\
(4g+2)(16g^2-8g+4)
3 0
3 years ago
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