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Solnce55 [7]
3 years ago
10

Which are solutions of the linear equation? Select all that apply. 3x + y = -10

Mathematics
2 answers:
koban [17]3 years ago
5 0

Answer:

Ans is in the attachment

Plz mark as brainliest

Hope it helps :)

Roman55 [17]3 years ago
3 0

Answer:

3x + y = -10

y = -3x-10

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Oh! I answered this question last week! Don't know if it was the same exact one, but whatever. So first cut the number of pages in Kate's report in half, then add 5 to that. So, (14÷2)+5
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Pls find the surface area for me. I need help ASAP!
melomori [17]

Answer:

About 90.84 in^2

Step-by-step explanation:

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3 0
3 years ago
Which of these relations on the set {0, 1, 2, 3} are equivalence relations? If not, please give reasons why. (In other words, if
Delicious77 [7]

Answer:

(1)Equivalence Relation

(2)Not Transitive, (0,3) is missing

(3)Equivalence Relation

(4)Not symmetric and Not Transitive, (2,1) is not in the set

Step-by-step explanation:

A set is said to be an equivalence relation if it satisfies the following conditions:

  • Reflexivity: If \forall x \in A, x \rightarrow x
  • Symmetry: \forall x,y \in A, $if x \rightarrow y,$ then y \rightarrow x
  • Transitivity: \forall x,y,z \in A, $if x \rightarrow y,$ and y \rightarrow z, $ then x \rightarrow z

(1) {(0,0), (1,1), (2,2), (3,3)}

(3) {(0,0), (1,1), (1,2), (2,1), (2,2), (3,3)}

The relations in 1 and 3 are Reflexive, Symmetric and Transitive. Therefore (1) and (3) are equivalence relation.

(2) {(0,0), (0,2), (2,0), (2,2), (2,3), (3,2), (3,3)}

In (2), (0,2) and (2,3) are in the set but (0,3) is not in the set.

Therefore, It is not transitive.

As a result, the set (2) is not an equivalence relation.

(4) {(0,0), (0,1), (0,2), (1,0), (1,1), (1,2), (2,0), (2,2), (3,3)}

(1,2) is in the set but (2,1) is not in the set, therefore it is not symmetric

Also, (2,0) and (0,1) is in the set, but (2,1) is not, rendering the condition for transitivity invalid.

5 0
3 years ago
Name one addition piece of information that is sufficient to prove that the triangles are similar. Please explain!
Sophie [7]

Answer:

the given triangles are right triangles which is enough to prove them 'similar'

but not congruent.

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3 years ago
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