Answer: 50.24 cm^2
Step-by-step explanation:
This can be translated to:
An old coin is kept in a cubic box in such a way that the outline of the coin touches the 4 walls of the box, if the base of the box has a perimeter of 24 cm. What is the area of the coin?
The fact that the coin touches the interior of the box means that the diameter of the coin is equal to the side lenght of the box.
The perimeter of the box is 24 cm, and the perimeter of a square is equal to:
P = 4*L
where L is the side lenght of the square.
24 cm = 4*L
L = 24cm/4 = 8cm
Now we know that the diameter of the coin is 8cm
Now, the area of a circle (the coin) is equal to:
A = 3.14*(d/2)^2
where d is the diameter, so we have:
A = 3.14*(4cm)^2 = 50.24 cm^2
(x3)(x4) is x7 because when you have a problem like that, you have to ADD your exponents.
-(m4)3 is -m12 since you're multiplying them.
(z3)5 is z15
y4 x y5 is y9
thats all i know of. hope it helps cx
ANSWER for the first one:
A=a+b/2*h
A= 4.5+9/2*6
A= 40.5 cm2
ANSWER for the second one:
9*3= 27
3*3= 9
9*3= 27
A= 63 cm2
16+2x
You can’t simplify anymore since there’s no other variable or whole number.
Answer:
ok,i know
Step-by-step explanation:
there is no like terms
