The answers are:
<span>ƒ(x) = x - .15x
</span><span>Sale = Original - .15(Original)
</span><span>y = .85x
Let sale price be f(x) and x be the original price. Discount was 15% = 0.15
f(x) = x - 0.15x
If f(x) is sale and x is the original, then:
</span><span>Sale = Original - .15(Original)
Let sale price be y and original price x:
y = x - 0.15x
y = 1 * x - 0.15 * x
y = (1 - 0.15) * x
y = 0.85x</span>
Answer:
2/3* 4/5 = 8/15
Step-by-step explanation:
I think your question is missed of key information, allow me to add in and hope it will fit the original one. Please have a look at the attached file below.
Given:
- One-fifth (1/5) of the playground is used for students to sit and read
- 2/3 is used for playing soccer
- The rest of the playground is used for playing basketball
So assume that the the playground is divided into 5 equal part
=> 1 part is used for students to sit and read or (1/5)
=> the remaining equal part is 4 or (4/5)
Because 2/3 of the remaining part is used for playing soccer
=> the equation represents the part of the playground used for soccer is:
2/3 of 4/5
= 2/3* 4/5
= 8/15
It would be 7x-9 because 2x squared would be 4x, and you can only simplify two numbers if they have the same variable after it. So, all you can do is simplify this equation down to 7x-9.
Answer: 4660
Step-by-step explanation:
Given
Weight of a single crate =50 kg
Maximum weight in the container =26500 kg
Other shipments weight =3200 kg
Here, x is the no of 50 kg crate
Weight of x crates and other shipments must be equal to or less than 26500 i.e.

subtracting 3200 both sides

So, maximum no of crates to be loaded are 4660