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3 years ago

(2x^4-3x^2+4x-9)÷(x+2)

Mathematics

1 answer:

dexar [7]3 years ago

3 0

Working is attached: 2x^3 - 4x^2 + 5x - 6 remainder 3

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Mia is drawing an angle that is made up of 35 one-degree angles. How many degrees is Mia's angle?

Tcecarenko [31]

Answer:

35 degrees

Step-by-step explanation:

add all the one degrees together

3 0

3 years ago

Write an equation of a line with the given slope and y-intercept

Verizon [17]

Y=mx+b
m=slope
b=yint

given
m=2
b=4/5
easy

y=2x+4/5

A

8 0

3 years ago

8h=28 how do you solve this

Rashid [163]

Answer:

h=3.5

Step-by-step explanation:

divide 28 by 8

hope I helped

5 0

3 years ago

Read 2 more answers

Solve the differential. This was in the 2016 VCE Specialist Maths Paper 1 and i'm a bit stuck

Nimfa-mama [501]

$\sqrt{2 - x^{2}} \cdot \frac{dy}{dx} = \frac{1}{2 - y}$
$\frac{dy}{dx} = \frac{1}{(2 - y)\sqrt{2 - x^{2}}}$

Now, isolate the variables, so you can integrate.
$(2 - y)dy = \frac{dx}{\sqrt{2 - x^{2}}}$
$\int (2 - y)\,dy = \int\frac{dx}{\sqrt{2 - x^{2}}}$
$2y - \frac{y^{2}}{2} = sin^{-1}\frac{x}{\sqrt{2}} + \frac{1}{2}C$

$4y - y^{2} = 2sin^{-1}\frac{x}{\sqrt{2}} + C$
$y^{2} - 4y = -2sin^{-1}\frac{x}{\sqrt{2}} - C$
$(y - 2)^{2} - 4 = -2sin^{-1}\frac{x}{\sqrt{2}} - C$
$(y - 2)^{2} = 4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C$

$y - 2 = \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}$
$y = 2 \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}$

At x = 1, y = 0.
$0 = 2 \pm\sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$
$-2 = \pm\sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$

$4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C > 0$
$\therefore 2 = \sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$

$4 = 4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C$
$0 = -2sin^{-1}\frac{1}{\sqrt{2}} - C$
$C = -2sin^{-1}\frac{1}{\sqrt{2}} = -2\frac{\pi}{4}$
$C = -\frac{\pi}{2}$

$\therefore y = 2 - \sqrt{4 + \frac{\pi}{2} - 2sin^{-1}\frac{x}{\sqrt{2}}}$

6 0

3 years ago

What is the minimum amount of saran wrap that Tyler will need to cover the pencil holder, to ensure that no sand leaks out? *

liberstina [14]

Answer:

Step-by-step explanation:

To find the surface area of the triangular prism, you need to find the area of all the sides and add them together. The two triangular bases have already been established to have an area of 3 square units each, so together they have an area of 6 units. Two of the rectangular sides have dimensions of 3.5 by 2.5 units, while one has dimensions 3.5 by 3 units. Adding all of this together, you get a total of 34 square inches, or option e. Hope this helps!

7 0

3 years ago