Answer:
<h2>
</h2>
Step-by-step explanation:
Let the length of the rectangle be l
Area of a rectangle = length × width
From the question
Area = 25/42
width = 5/6
Substitute the values into the above formula and solve for the length
That's
<h3>
</h3>
So we have
<h3>
</h3>
We have the final answer as
<h3>
</h3>
Hope this helps you
The surface area of rectangular prism is 360 square inches
<em><u>Solution:</u></em>
Given that rectangular prism of the length is 18 cm the width 6 cm and the height 3 cm
To find: Surface area of rectangular prism
<em><u>The Surface area of rectangular prism is given by formula:</u></em>
Where,
"l" is the length and "h" is the height and "w" is the width of prism
From given,
l = 18 cm
w = 6 cm
h = 3 cm
<em><u>Substituting the values in formula,</u></em>
Thus surface area of rectangular prism is 360 square inches
<h3>
Answer: No, it is not a function</h3>
If you can draw a vertical line through more than one point on the curve, then it's not a function. In this case, we can draw such a line. The graph is said to have failed the vertical line test.
What this means is that some x inputs lead to more than one y outputs. A function is only possible if any x input leads to exactly one y output. The x input must be in the domain.
Answer:
4.3cm
Step-by-step explanation:
the radius of the hemisphere can be determined its volume
volume of a hemisphere = (2/3) x (n) x (r^3)
n = 22/7
r = radius
(2/3) x (22/7) x( r^3) = 165 cm^3
44/21 x r^3 = 165
divide both sides of the equation by 21/44
165 x 21/44
r^3 = 78.75
find the cube root
r = 4.2863 cm
the tenth is the first number after the decimal place. To convert to the nearest tenth, look at the number after the tenth (the hundredth). If the number is greater or equal to 5, add 1 to the tenth figure. If this is not the case, add zero
the 100th terms, 8 is greater than 6, so add 1 to 2. this give 4.3cm
Answer: 1/32
Step-by-step explanation: Each day, the fraction/number is dividing by 2. Therefore, day 5 would be 1/16, and 1/16 divided by 2 would be 1/32.
