Answer:
Step-by-step explanation:
we have
we know that
In this problem
substitute in the formula
Okay so 300 meters per minute and he ran 8 minutes..
300x8=2400
He still had 600 left to go...
2400+600=3,000
He had to run three times longer than Eric...
3000/3=1000
Does that make sense?
Answer:
P ( 5 < X < 10 ) = 1
Step-by-step explanation:
Given:-
- Sample size n = 49
- The sample mean u = 8.0 mins
- The sample standard deviation s = 1.3 mins
Find:-
Find the probability that the average time waiting in line for these customers is between 5 and 10 minutes.
Solution:-
- We will assume that the random variable follows a normal distribution with, then its given that the sample also exhibits normality. The population distribution can be expressed as:
X ~ N ( u , s /√n )
Where
s /√n = 1.3 / √49 = 0.2143
- The required probability is P ( 5 < X < 10 ) minutes. The standardized values are:
P ( 5 < X < 10 ) = P ( (5 - 8) / 0.2143 < Z < (10-8) / 0.2143 )
= P ( -14.93 < Z < 8.4 )
- Using standard Z-table we have:
P ( 5 < X < 10 ) = P ( -14.93 < Z < 8.4 ) = 1
Answer:
Yes it can be solved.
Step-by-step explanation:
I did this stuff in like 4th grade lollll
Answers are A and E, this is because you can do 3:12 x 4 = 12:48 and 3:12/4 = 1:4 therefore they are all equal values
