Money earned by restaurant on Friday=$1073
Money earned by restaurant on Saturday=$1108
Let Money earned by restaurant on Sunday=$x
Average=$1000
Number of observation=3
⇒ 3× 1000=1073+1108+x
⇒3000= 2 181+x
⇒3000-2181=x
⇒x=819
The restaurant needs to earn on Sunday to average $1000 per day over the three-day period=$819
1: 40%
2: 30%
3: 20%
If we know one of the succeeded, then
1: 44.44%
2: 33.33%
3: 22.22%
If under the circumstance that they all fail to meet a strong leader, the board picks one of them at random,
1: 43.33%
2: 33.33%
3: 23.33%
The first person has a 2 in 5 chance of randomly getting a strong leader. If the first person doesn't find a strong leader, the second person has a 2/4 chance of getting a strong leader. If neither the first nor second person gets a strong leader, the third sales person has a 2/3 chance of getting a strong leader.
1: 2/5=40% Chance
2: (3/5)*(2/4)=30% Chance You have to take the probability the first rep failed to get a strong leader, then multiply by the probability the second rep gets a strong leader.
3: (3/5)*(2/4)*(2/3)=20% You have to take the probability both the other people failed, then multiply by the probability they succeeded.
Answer:
A
Step-by-step explanation:
Hopefully this helps!
Answer:
2^K≥40
2^5≥20
24/5 =4.75
40 books= 40/5 = 8 mean
9 2's
10 7's
13 12's
2 17's
6 22's
18+70+156+34+132= 410/40 =10.25
150+156+70=306+70=376/40 books bought = 9.4 mean
Step-by-step explanation:
