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fgiga [73]
3 years ago
10

The sum of two consecutive odd integers is 236. What is the smaller integer?

Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
8 0

Answer:

D. 113

Step-by-step explanation:

If you take the other numbers and subtract each from the original 236, they all exceed the amount. So the answer would be 113.

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Which of the following represents the correct inequality statements
m_a_m_a [10]

Answer:


Step-by-step explanation:


3 0
3 years ago
Find the values of the pronumerals in this diagram. Write down the reason in each case.
timofeeve [1]

Answer:

see explanation

Step-by-step explanation:

a and 85 form a straight angle and are supplementary, thus

a + 85 = 180 ( subtract 85 from both sides )

a = 95

b and 85 are vertical angles and are congruent, thus

b = 85

c and 85 are corresponding angles and congruent, thus

c = 85

c and d are vertical angles and congruent, thus

d = 85

In conclusion

a = 95, b = 85, c = 85, d = 85

5 0
3 years ago
The sum of three consecutive odd numbers is 123 what is the smallest of the three numbers
Inga [223]

Answer:

39

Step-by-step explanation:

Let the three consecutive odd numbers be:

x+2, x+4, x+6.

The sum of the consecutive numbers is 123 i.e

x+2 + (x+4) + (x+6) = 123

x + 2 + x + 4 + x + 6 = 123

3x + 12 = 123

Collect like terms

3x = 123 — 12

3x = 111

Divide both side by the coefficient of x i.e 3

x = 111/3

x = 37

Now let us find the value of the three odd numbers. This is illustrated:

1st : x + 2 = 37 + 2 = 39

2nd : x + 4 = 37 + 4 = 41

3rd : x + 6 = 37 + 6 = 43

The smallest of the three consecutive odd numbers is 39

5 0
3 years ago
Determine the value for b assuming that the two horizontal lines displayed are parallel.
Neko [114]

Answer:

29

Step-by-step explanation:

8 0
3 years ago
What is the area of a cross section that is parallel to face CDHG ?
Dennis_Churaev [7]

Answer: Area of cross section that is parallel to face CDHG is 432 cm².

Step-by-step explanation:

Since we have given that

There is a cross section that is parallel to face CDHG.

So, Length of cross section would be 36 cm

Width of cross section would be 12 cm.

So, Area of cross section would be

Length\times breadth\\\\=36\times 12\\\\=432\ cm^2

Hence, Area of cross section that is parallel to face CDHG is 432 cm².

8 0
3 years ago
Read 2 more answers
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