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mart [117]
3 years ago
11

Ames earned $816 each year. He earned x dollars less per month than Matt, who earned $80 per month.

Mathematics
2 answers:
r-ruslan [8.4K]3 years ago
4 0

Answer: Its B and C

Step-by-step explanation:

earnstyle [38]3 years ago
4 0

Answer:

The correct answer is:

B. Substitute 12 for x in the equation

C. Multiply $68 by 12 months

You might be interested in
What is 50% of $68? Show all of your work. Use the percent proportion model shown below to set up the equation before you calcul
Natali5045456 [20]

Answer:

$34

Step-by-step explanation:

50% is half of 100%

(Because 50% x 2 = 100%)

Thus, half the money ($68) to find 50%.

So, 68÷2 = 34

Final answer is $34

Or

50/100 x $68 =$34

Hope this helps!

6 0
2 years ago
1. Evaluate -3x^3 -2y^2 when x=-5 and y =3
-Dominant- [34]

Answer:

357

Step-by-step explanation:

A) We replace x = - 5 and u = 3 into -3x^3 -2y^2

and we have -3x^3 -2y^2= -3*(-5)^3 -2*3^2= -3*(-125)- 2*9

or -3x^3 -2y^2 = 375-18= 357

The answer is 357.

B) Replace h = -2 into h^2-3h+2

we have h^2-3h+2 = (-2)^2 -3*(-2) +2 = 4 +6 + 2= 12

The answer is 12

Have a good day.

8 0
4 years ago
What is the expanded form of 9,003,840,165
babunello [35]
9,000,000,000 + 3,000,000 + 800,000 + 40,000 + 100 + 60 + 5. Give brainliest please.
7 0
4 years ago
Read 2 more answers
Whats 9+10??????????
nikdorinn [45]
The answer to 9+10 is 19 because if you add 9 to the number 10, you get 19
3 0
4 years ago
Read 2 more answers
The figure below is a square. Find the length of side x in simplest radical form with a rational denominator.
Mashcka [7]

Answer:

\frac{\sqrt{10}}{2}

Step-by-step explanation:

The diagonal forms two 45-45-90 triangles, with the diagonal being the hypotenuse of both. The Pythagorean Theorem states that a^2+b^2=c^2, where c is the hypotenuse of the triangle, and a and b are the two legs of the triangle.

From the Isosceles Base Theorem, the two legs of a 45-45-90 triangle are always equal. Since we're given a diagonal of \sqrt{5}, we have:

x^2+x^2=\sqrt{5}^2,\\2x^2=5,\\x^2=\frac{5}{2},\\x=\sqrt{\frac{5}{2}}=\frac{\sqrt{5}}{\sqrt{2}}=\frac{\sqrt{5}}{\sqrt{2}}\cdot \frac{\sqrt{2}}{\sqrt{2}}=\boxed{\frac{\sqrt{10}}{2}}

7 0
3 years ago
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