A = 21/2 i will write something too just to fill up the space
Answer:
14 +15 the answer is this
Here are the steps
1: Put the compass on Q and make the width equal to the distance from Q to L. Extend line LM towards the left side of L and draw an arc hitting the line segment on the left side of L
2. <span> Without changing the width and position of the compass, draw an arc between L and M.
3. Without changing the width of the compass, put the compass on the point of intersection of the arc and line LM (left side of L). Draw an arc above line LM.
4. Without changing the width of the compass, put the compass on the point of intersection of the arc and line LM (right side of L). Draw an arc above line LM.
5. Use a straight edge to make a line from the intersection of the two arcs above line LM to Q intersecting through L along the way. </span>
Answer:
Step-by-step explanation:
Researchers measured the data speeds for a particular smartphone carrier at 50 airports.
The highest speed measured was 76.6 Mbps.
n= 50
X[bar]= 17.95
S= 23.39
a. What is the difference between the carrier's highest data speed and the mean of all 50 data speeds?
If the highest speed is 76.6 and the sample mean is 17.95, the difference is 76.6-17.95= 58.65 Mbps
b. How many standard deviations is that [the difference found in part (a)]?
To know how many standard deviations is the max value apart from the sample mean, you have to divide the difference between those two values by the standard deviation
Dif/S= 58.65/23.39= 2.507 ≅ 2.51 Standard deviations
c. Convert the carrier's highest data speed to a z score.
The value is X= 76.6
Using the formula Z= (X - μ)/ δ= (76.6 - 17.95)/ 23.39= 2.51
d. If we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant?
The Z value corresponding to the highest data speed is 2.51, considerin that is greater than 2 you can assume that it is significant.
I hope it helps!
