To Find :
How many gallons of a 80% antifreeze solution must be mixed with 100 gallons of 20% antifreeze to get a mixture that is 70% antifreeze.
Solution :
Let, x gallons of 80% antifreeze solution is required :
So,
Therefore, 500 gallons of 80% antifreeze solution is required.
Answer:
Step-by-step explanation:
-8 -8
₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋
⇵
Answer:
4
Step-by-step explanation:
The slope of the line is given. It is 4. Use the equation y=mx+b to answer the other questions.
Substitute 1 in for y, 4 in for m, and 2 in for x and solve for b. The equation would look like 1=4(2)+b.
Solving that equation will give you b=-7
That means the y-intercept is -7.
The equation would then be y=4x-7
