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ki77a [65]
3 years ago
14

Harvey the wonder hamster can run 3 1/6 km in 1/4 hour. Harvey runs at a constant rate. Find his average speed in kilometers per

hour
Mathematics
2 answers:
inysia [295]3 years ago
7 0
3 \frac{1}{6}: \frac{1}{4}= \frac{19}{6}* \frac{4}{1}= \frac{38}{3}=     12 \frac{2}{3}

<span>his average speed is </span>12 2/3 kilometers per hour
algol [13]3 years ago
5 0

The average speed of an object is computed as follows,

v=\frac{d}{t} , where d is the distance covered in the time interval of interest and  t  is the time taken  to cover the distance.


In this problem, the distance covered is

d= 3\frac{1}{6} km =\frac{19}{6} km. as an equivalent fraction.

The time taken for the journey is

t=\frac{1}{4} hour..

The avarage is speed is then,

v=\frac{d}{t}

v=\frac{(19/6)km}{(1/4)h} =\frac{19\times 4 km}{6\times 1h} =\frac{38km}{3h} = 12.67km/h.

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3. Answer: 35x+12

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4 0
3 years ago
3. A survey conducted among a group of 50 students showed that; (APPLYING)
Pani-rosa [81]

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Step-by-step explanation:

this is a set problem (mathematical set)

30 students played soccer

9 students played cricket and soccer

x students played neither cricket nor soccer

3x students played cricket only.

we can see that in the first set 21 appears and in the middle of the set 9 because it says 30 students played soccer adding x and 3x we have the following formula

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5 0
3 years ago
(b) A department store has 7,000 charge accounts. The comptroller takes a random sample of 36 of
galben [10]

Answer:

a.0.8664

b. 0.23753

c. 0.15866

Step-by-step explanation:

The comptroller takes a random sample of 36 of the account balances and calculates the standard deviation to be N42.00. If the actual mean (1) of the account balances is N175.00, what is the probability that the sample mean would be between

a. N164.50 and N185.50?

b. greater than N180.00?

c. less than N168.00?

We solve the above question using z score formula

z = (x-μ)/σ/√n where

x is the raw score,

μ is the population mean = N175

σ is the population standard deviation = N42

n is random number of sample = 36

a. Between N164.50 and N185.50?

For x = N 164.50

z = 164.50 - 175/42 /√36

z = -1.5

Probability value from Z-Table:

P(x = 164.50) = 0.066807

For x = N185.50

z = 185.50 - 175/42 /√36

z =1.5

Probability value from Z-Table:

P(x=185.50) = 0.93319

Hence:

P(x = 185.50) - P(x =164.50)

= 0.93319 - 0.066807

= 0.866383

Approximately = 0.8664

b. greater than N180.00?

x > N 180

Hence:

z = 180 - 175/42 /√36

z = 5/42/6

z = 5/7

= 0.71429

Probability value from Z-Table:

P(x<180) = 0.76247

P(x>180) = 1 - P(x<180) = 0.23753

c. less than N168.00?

x < N168.

z = 168 - 175/42 /√36

z = -7/42/6

z = -7/7

z = -1

Probability value from Z-Table:

P(x<168) = 0.15866

4 0
3 years ago
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