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ki77a [65]
4 years ago
14

Harvey the wonder hamster can run 3 1/6 km in 1/4 hour. Harvey runs at a constant rate. Find his average speed in kilometers per

hour
Mathematics
2 answers:
inysia [295]4 years ago
7 0
3 \frac{1}{6}: \frac{1}{4}= \frac{19}{6}* \frac{4}{1}= \frac{38}{3}=     12 \frac{2}{3}

<span>his average speed is </span>12 2/3 kilometers per hour
algol [13]4 years ago
5 0

The average speed of an object is computed as follows,

v=\frac{d}{t} , where d is the distance covered in the time interval of interest and  t  is the time taken  to cover the distance.


In this problem, the distance covered is

d= 3\frac{1}{6} km =\frac{19}{6} km. as an equivalent fraction.

The time taken for the journey is

t=\frac{1}{4} hour..

The avarage is speed is then,

v=\frac{d}{t}

v=\frac{(19/6)km}{(1/4)h} =\frac{19\times 4 km}{6\times 1h} =\frac{38km}{3h} = 12.67km/h.

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The number of failures of a testing instrument from contamination particles on the product is a Poisson random variable with a m
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Answer:

a) There is an 81.87% probability that the instrument does not fail in an 8-hour shift.

b) There is a 45.12% probability of at least one failure in a 24-hour day.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

a. What is the probability that the instrument does not fail in an 8-hour shift?

The mean for an hour is 0.025 failures.

For 8 hours, we have \mu = 8*0.025 = 0.2

This probability is P(X = 0).

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-0.2}*(0.2)^{0}}{(0)!} = 0.8187

There is an 81.87% probability that the instrument does not fail in an 8-hour shift.

b. What is the probability of at least one failure in a 24-hour day?

The mean for an hour is 0.025 failures.

For 24 hours, we have \mu = 24*0.025 = 0.6

Either we have at least one failure, or we have no failures. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-0.6}*(0.2)^{0}}{(0)!} = 0.5488

So

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.5488 = 0.4512

There is a 45.12% probability of at least one failure in a 24-hour day.

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