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fgiga [73]
3 years ago
8

Find all the zeros of

3%7D%20%20-%20%20%7B4x%7D%5E%7B2%7D%20%20%2B%207x%20-%202" id="TexFormula1" title="f(x) = {6x}^{4} - {7x}^{3} - {4x}^{2} + 7x - 2" alt="f(x) = {6x}^{4} - {7x}^{3} - {4x}^{2} + 7x - 2" align="absmiddle" class="latex-formula">
​

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
5 0

Answer:

  {-1, 1/2, 2/3, 1}

Step-by-step explanation:

I find a graphing calculator to be a most useful tool for problems like this. (See attached.)

_____

First of all, observe that the constant is -2, so 0 is not a zero.

It is often useful to look at the sum of coefficients. Here, that is 0, indicating 1 is a zero.

You can divide that out, or simply continue by looking at the sum of coefficients with odd-degree terms negated. Then you have 6 +7 -4 -7 -2 = 0, indicating -1 is also a zero.

__

At this point, it can be useful to divide out the factors you know. The synthetic division tableaus attached show that work. First is division by (x+1), then by (x -1).

The result of doing that is the quadratic ...

  6x^2 -7x +2 = 0

This can be factored ...

  (6x^2 -3x) -(4x -2) = 0 . . . . . . rewrite -7x and group term pairs

  3x(2x -1) -2(2x -1) = 0 . . . . . . . factor each pair

  (3x -2)(2x -1) = 0 . . . . . . the factorization of the remaining quadratic

The zeros of this are the values of x that make the factors zero: 2/3 and 1/2.

The zeros of the given function f(x) are x ∈ {-1, 1/2, 2/3, 1}.

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I need help I don't know how to do this ​
Trava [24]

Answer:

Median = 7

upper quartile = 10

lower quartile is 6

Step-by-step explanation:

The median is the middle line in the box

Median = 7

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The lower quartile is the left line of the box

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4 0
3 years ago
A figure has vertices at L(3,3), M(2,4), and N(−1,0). After a transformation, the image of the figure has vertices at L′(2,−5),
alexandr402 [8]

The transformation was a reflection over the line x = -0.5

And the image and preimage can be seen in the graph below.

<h3>How to identify the preimage and image?</h3>

First, the original vertices are:

L(3, 3)

M(2, 4)

N(-1, 0)

3 vertices means that our figure is a triangle.

Now, the transformed vertices are:

L'(2, -5)

M'(3, -4)

N'(-1, 1)

And the graph of both sets can be seen below.

Now we can try to identify the transformation.

Now, notice that all the points (L, M, N, L', N', M') are equidistant to the horizontal line x = -0.5

This is a clear implication that the transformation was a reflection over the line x = -0.5

If you want to learn more about transformations:

brainly.com/question/4289712

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3 0
1 year ago
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