Let's assume the three consecutive integers are x, x+1 and x+2.
So, sum of x, x+1 and x+2 can be written as x+x+1+x+2.
Twice the middle integer (x+1) will be 2*(x + 1).
Hence 3 more than 2(x+1) can be represent as 3 + 2(x+1).
Hence, we can set u the following equation as following:
x + x + 1 + x + 2 = 3 + 2(x + 1).
3x + 3 = 3 + 2x + 2
3x + 3 = 2x + 5 Combine the like terms.
3x + 3- 3 = 2x + 5 - 3 Subtract 3 from each sides.
3x = 2x + 2
3x - 2x = 2x + 2 - 2x Subtract 2x from each sides.
x = 2
So, the first integer is 2.
Second integer is 2+ 1 = 3 and
Third integer 2+2 = 4
So, the three consecutive integers are 2, 3 and 4.
"Hope this helps!!"
