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Margarita [4]
3 years ago
8

State the domain of the following relation and state if it is a function. (2, 4), (8, 6), (5, 5), (2, 7), (4, 5)

Mathematics
1 answer:
Makovka662 [10]3 years ago
4 0
NOT a function ......................... :)
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The annual precipitation amounts in a certain mountain range are normally distributed with a mean of 104 inches, and a standard
dsp73

Answer:

91.92% probability that the mean annual precipitation during 49 randomly picked years will be less than 106.8 inches

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 104, \sigma = 14, n = 49, s = \frac{14}{\sqrt{49}} = 2

What is the probability that the mean annual precipitation during 49 randomly picked years will be less than 106.8 inches

This is the pvalue of Z when X = 106.8. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{106.8 - 104}{2}

Z = 1.4

Z = 1.4 has a pvalue of 0.9192

0.9192 = 91.92% probability that the mean annual precipitation during 49 randomly picked years will be less than 106.8 inches

8 0
3 years ago
Plz help I need your help plz help me plz I swear I need your help plz help me plz I’m begging you on my 2 knees plz help me
REY [17]

Answer:

The correct answer is B

Step-by-step explanation:

First, the question said that the shoes were $15 less than double the price of his pants. In algebra 2p would mean 2 multiplied by p so we know that C and D are wrong. Now $15 less than 2p would mean you have to subtract by 15, so now we have 2p-15. Since we haven't added in the amount of money the pair of pants cost, we have to use addition to add it in, and that adds to the equation making the equation 2p - 15 + p. So, the answer is B.

6 0
3 years ago
Which equation shows function notation for a vertical stretch of factor 2 and shift right 5 units? *
liubo4ka [24]

Answer: I am doing an giveaway for and iphone 11 pro max (black)

Step-by-step explanation: first person who message me gets it be the first

7 0
3 years ago
Please help me give me right answer pleaseeeeeeeeeeee
Harlamova29_29 [7]

Answer:

7 x 2, 14, the area, then use pie, 3.14 to get the circle

Step-by-step explanation:

3 0
2 years ago
B A pair of fair dice is rolled, If the sum of the spots is 7, determine the probability that one di showed a 2.
finlep [7]

Answer:

\text{Probability}=\frac{1}{3}

Step-by-step explanation:

Given : A pair of fair dice is rolled, If the sum of the spots is 7.

To find : Determine the probability that one die showed a 2 ?

Solution :

A pair of fair dice is rolled the outcomes are,

(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)

(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)

(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

The sum of the spots is 7 i.e. (4,3),(2,5),(5,2),(3,4),(1,6),(6,1).

Total possibility = 6

Favorable outcome is that one die showed a 2 i.e. (2,5),(5,2)= 2

The probability that one die showed a 2 is given by,

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total outcome}}

\text{Probability}=\frac{2}{6}

\text{Probability}=\frac{1}{3}

8 0
2 years ago
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