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2 years ago

Find the equation of a line passing through the points (2,1) and (5,10) in slope intercept form.

Mathematics

1 answer:

guajiro [1.7K]2 years ago

4 0

Answer:

y=3x-5

Step-by-step explanation:

Slope intercept form is y=mx+b

m represents slope

b represents y-intercept

In the picture, 3 replaces m, so 3 is the slope of the line.

When (2,1) and (5,10) are graphed, the line intercepts -5 on the y axis.

-5 is the y-intercept.

So, (2,1) and (5,10) in slope-intercept form is $y=3x-5$

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If I make 11.50 an hour working full time (40 hours a week) how much money do i make a year after deducting 60 dollars of taxes

Kazeer [188]

Given:
hourly rate = 11.50
hours worked in a week = 40 hours
taxes per moth = 60

Every month may be 4 weeks or 5 weeks but we know that 1 year has 52.1429 weeks.

Let us compute for the whole year:

Earnings:
11.50 /1 hour * 40 hours/1week * 52.1429 weeks/1year
= 11.50 * 40 * 52.1429/year
= 23,985.734 per year

Taxes:
60 / per month * 12 months / 1 year
= 60 * 12/year
= 720 per year

Net earning per year
23,985.734 - 720 = 23,264.734

Net earning per month
23,264.734 ÷ 12 months = 1,938.81

You will earn 23,264.73 annually from a monthly earning of 1,938.81

7 0

3 years ago

Area of a circular ring: A = 4<img src="https://tex.z-dn.net/?f=%20%5Cpi%20" id="TexFormula1" title=" \pi " alt=" \pi " align="a

OleMash [197]

1a) A = 4πpw
   /4πw = /4πw
A / 4πw = p

1b) A = 4πpw
22 = 4πp(2)
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2a) P = 2πr + 2x
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/2π /2π
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2b) P = 2πr + 2x
440 = 2πr + 2(110)
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3 years ago

I need help please.!

gulaghasi [49]

Hey ! I know for sure A is one of the correct answers i’m working on the rest now

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3 years ago

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erik [133]

Answer:

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Step-by-step explanation:

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3 years ago

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Olin [163]

Step-by-step explanation:

$\frac{\sin \:4A}{\cos \:2A} \times \frac{1 - \cos \:2A}{1 - \cos\:4A} = \tan \:A \\ \\ LHS = \frac{\sin \:4A}{\cos \:2A} \times \frac{1 - \cos \:2A}{1 - \cos\:4A} \\ \\ = \frac{2\sin \:2A.\cos \:2A}{\cos \:2A} \times \frac{1 - (2 { \cos}^{2}A - 1) }{1 - (2 { \cos}^{2}2A - 1) } \\ \\ = 2\sin \:2A \times \frac{1 - 2 { \cos}^{2}A + 1}{1 - 2 { \cos}^{2}2A + 1 } \\ \\ = 2\sin \:2A \times \frac{2- 2 { \cos}^{2}A }{2 - 2 { \cos}^{2}2A } \\ \\ = 2\sin \:2A \times \frac{2(1 - { \cos}^{2}A) }{2 (1- { \cos}^{2}2A) } \\ \\ = 2\sin \:2A \times \frac{1 - { \cos}^{2}A}{1- { \cos}^{2}2A } \\ \\ = 2\sin \:2A \times \frac{ { \sin}^{2}A}{{ \sin}^{2}2A } \\ \\ = 2 \times \frac{ { \sin}^{2}A}{{ \sin}2A } \\ \\ = 2 \times \frac{ { \sin}^{2}A}{{ 2\sin}A. \cos \: A } \\ \\ = \frac{ { \sin}A}{ \cos \: A } \\ \\ = tan \: A \\ \\ = RHS \\$

7 0

3 years ago

Find the equation of a line passing through the points (2,1) and (5,10) in slope intercept form.​

Find the equation of a line passing through the points (2,1) and (5,10) in slope intercept form.