Calcium Hydroxide (Ca(OH)2) can actually be formed by the
reaction of Calcium Oxide (CaO) with water (H2O). The complete balanced
chemical reaction is:
<span>CaO + H2O
--> Ca(OH)2</span>
<span>The subscript 2 in (OH) means that there are 2 O and 2 H
on the product side. Hence, the equation is balanced already.</span>
A statement from the laboratory report which best represents a conclusion for this investigation is that: D. students who spend less time studying after school get lower math grade.
<h3>What is a research?</h3>
A research is also referred to a study and it can be defined as an investigation which typically involves the process of manipulating an independent variable (the cause), in order to determine or measure the dependent variable (the effect) and reach a logical conclusion with results.
<h3>What is an analytical research report?</h3>
An analytical research report can be defined as a well-crafted and written document that is typically used by a researcher to display a detailed analysis of the information which are obtained through a particular research method.
In this scenario, we can infer and logically deduce that a statement from the laboratory report which best represents a conclusion for this investigation is that the group of students who spend less time studying after school would get lower math grade.
Read more on analytical research here: brainly.com/question/17137042
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Answer: The temperature of the gas is 132.25K and -140.75°C
Explanation:
Given that:
Volume of helium gas (V) = 18.5L
Temperature of helium gas (T) = ?
Pressure (P) = 0.85 atm
Number of moles (n) = 1.45 moles
Molar gas constant (R) is a constant with a value of 0.082 atm L K-1 mol-1
Then, apply the formula for ideal gas equation
pV = nRT
0.85atm x 18.5L = 1.45 moles x 0.082 atm L K-1 mol-1 x T
15.725 atm•L = 0.1189 atm•L•K-1 x T
T = 15.725 atm•L / 0.1189 atm•L•K-1
T = 132.25K
Given that temperature in Kelvin is 132.25, convert it to Celsius by subtracting 273
So, T(in Celsius) = 132.25K - 273
= -140.75°C
Thus, the temperature of the gas is 132.25K and -140.75°C
