Answer:
50%
Explanation:
This question involves a gene coding for eye color in humans. The allele for brown eyes (B) are dominant to blue eyes (b). This means that blue-eyed individual will possess genotype: bb.
According to this question, a blue-eyed man (bb) has children with a brown-eyed woman (B_) whose mother has blue eyes (bb). Since the mother of the brown-eyed woman has a blue eye, this means that the woman will be heterozygous for brown eye (Bb).
Hence, the parents in this question will cross as follows: blue eyed man (bb) × brown-eyed woman (Bb). The offspring/children will have the following genotypes (see attached punnet square); Bb, Bb, bb, bb.
Based on the question, 2/4 = 1/2 of the children will be heterozygous for the eye color trait. That is, ½ × 100 = 50%.
<span>Meiosis is different between male and females. In human </span>males,meiosis<span> occurs in the seminiferous tubules of the testicles while in </span>females<span>, it occurs in cells called as oogonia in </span>males<span>, it occurs at puberty and in </span>females it generates right after the time of the birth. I hope my answer has come to your help. God bless and have a nice day ahead!
Answer:
I think that this would be B, but I am not 100% sure
Explanation:
Bias in research is described as a "systematic error" so that is why I chose B.
Answer:
is because she wants you man. there no mom that dose not like their child