Answer:
E) Either anaphase I or II
Explanation:
Failure of segregation of homologous chromosomes during anaphase I or failure of segregation of sister chromatids during anaphase II leads to the presence of the abnormal number of chromosomes in resultant gametes. In the given example, the egg mother cell with 48 chromosomes (24 pairs) would enter meiosis I but the failure of one pair of homologous chromosomes to segregate from each other followed by normal meiosis II would result in the formation of two gametes with one extra chromosome and two gametes with one less chromosome.
On the other hand, if the nondisjunction occurs at anaphase II of meiosis II, two normal gametes, one gamete with one extra chromosome and one gamete with one less chromosome will be formed. Therefore, nondisjunction at anaphase I or anaphase II would have resulted in the production of eggs with one extra chromosome.
When there is not enough oxygen for cells to use cellular respiration<span />
<span>Taxol block the depolymerization of the microtubule that occurs during the anaphase of M phase in which the chromosomes are pulled towards opposite pole. Due to lack of pulling, separation of the chromosomes is not possible. Hence the cells will be arrested at M phase checkpoint</span>
Answer:
There are four major classes of biological macromolecules.1.)carbohydrates 2.)lipids 3.)proteins 4.)nuclic acids .each is an important cell component a performs a wide array of functions.
I believe it is the second option
Eukaryota and most likely produces milk to feed its young
