Answer:
5√3 ft/s
Step-by-step explanation:
Let h represent the horizontal distance of the kite from the person. Let s represent the string length. Then the Pythagorean theorem tells us ...
s^2 = 100^2 + h^2
2s·ds/dt = 0 + 2h·dh/dt
ds/dt = (h/s)·dh/dt
So, we need to know the horizontal distance when s=200.
200^2 = 100^2 + h^2
40000 -10000 = h^2
h = 100√3
Substituting known values into the equation for ds/dt, we have ...
ds/dt = (100√3)/(200)(10 ft/s) = 5√3 ft/s
The string must be let out at 5√3 ft/s when it is already 200 ft long.
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Answer:
A=l•w
A=6•10
A=60 yards square
1 yr sq 4$
60 yr sq x$
x=60•4/1
x=240 $
It would cost 240$ to carpet the room
Step-by-step explanation:
Answer:
-4 and -16
Step-by-step explanation:
Let x = first number
Let y = second number
Given:
- The two numbers multiply to 64
⇒ xy = 64
Given:
- The two numbers add to -20
⇒ x + y = -20
Rewrite x + y = -20 to make x the subject:
⇒ x = -20 - y
Substitute into xy = 64 and solve for y:
⇒ (-20 - y)y = 64
⇒ -20y - y² = 64
⇒ y² + 20y + 64 = 0
⇒ (y + 4)(y + 16) = 0
⇒ y = -4, y = -16
As x + y = -20
If y = -4 then x = -16
If y = -16 then x = -4
Therefore, the two numbers are -4 and -16
