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3 years ago

Which statement is true regarding the graphed functions?

Mathematics

2 answers:

elena55 [62]3 years ago

8 0

The Answer is c I had this question yesterday

Zigmanuir [339]3 years ago

4 0

Answer:

the answer to your question is f(2)=0 and g(-2)=0

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Find the value of the indicated angles. HELP PLEASE!!

balu736 [363]

Answer:

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3 years ago

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Write the equation in slope intercept form?

Anika [276]

Answer:

the third one

Step-by-step explanation:

add 2y and 16 to both sides. then divide by 2

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3 years ago

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For each vector field f⃗ (x,y,z), compute the curl of f⃗ and, if possible, find a function f(x,y,z) so that f⃗ =∇f. if no such f

butalik [34]

$\vec f(x,y,z)=(2yze^{2xyz}+4z^2\cos(xz^2))\,\vec\imath+2xze^{2xyz}\,\vec\jmath+(2xye^{2xyz}+8xz\cos(xz^2))\,\vec k$

Let

$\vec f=f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k$

The curl is

$\nabla\cdot\vec f=(\partial_x\,\vec\imath+\partial_y\,\vec\jmath+\partial_z\,\vec k)\times(f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k)$

where $\partial_\xi$ denotes the partial derivative operator with respect to $\xi$ . Recall that

$\vec\imath\times\vec\jmath=\vec k$

$\vec\jmath\times\vec k=\vec i$

$\vec k\times\vec\imath=\vec\jmath$

and that for any two vectors $\vec a$ and $\vec b$ , $\vec a\times\vec b=-\vec b\times\vec a$ , and $\vec a\times\vec a=\vec0$ .

The cross product reduces to

$\nabla\times\vec f=(\partial_yf_3-\partial_zf_2)\,\vec\imath+(\partial_xf_3-\partial_zf_1)\,\vec\jmath+(\partial_xf_2-\partial_yf_1)\,\vec k$

When you compute the partial derivatives, you'll find that all the components reduce to 0 and

$\nabla\times\vec f=\vec0$

which means $\vec f$ is indeed conservative and we can find $f$ .

Integrate both sides of

$\dfrac{\partial f}{\partial y}=2xze^{2xyz}$

with respect to $y$ and

$\implies f(x,y,z)=e^{2xyz}+g(x,z)$

Differentiate both sides with respect to $x$ and

$\dfrac{\partial f}{\partial x}=\dfrac{\partial(e^{2xyz})}{\partial x}+\dfrac{\partial g}{\partial x}$

$2yze^{2xyz}+4z^2\cos(xz^2)=2yze^{2xyz}+\dfrac{\partial g}{\partial x}$

$4z^2\cos(xz^2)=\dfrac{\partial g}{\partial x}$

$\implies g(x,z)=4\sin(xz^2)+h(z)$

Now

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+h(z)$

and differentiating with respect to $z$ gives

$\dfrac{\partial f}{\partial z}=\dfrac{\partial(e^{2xyz}+4\sin(xz^2))}{\partial z}+\dfrac{\mathrm dh}{\mathrm dz}$

$2xye^{2xyz}+8xz\cos(xz^2)=2xye^{2xyz}+8xz\cos(xz^2)+\dfrac{\mathrm dh}{\mathrm dz}$

$\dfrac{\mathrm dh}{\mathrm dz}=0$

$\implies h(z)=C$

for some constant $C$ . So

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+C$

3 0

3 years ago

Larisa earns $7 per hour.she worked 40 hours at the regular rate, 3 hours at time and half, and 6 hours at double time.

VARVARA [1.3K]

Answer:

$6.07/hr. if I understand the question properly. See below.

Step-by-step explanation:

I don't see the question, but will assume we want to find Larisa's base pay. The $7/hr given is the average for the work sequence noted in the problem. If this is incorrect, ignore the answer.

==================================

Let x be Larisa's base salary. We are told, I think, that in one stretch of time Larisa earned an average of $7/hour. That was composed of:

Hours Rate($/hr)

40 x

3 1.5x

6 2x

Her total income over this period would be:

40x +3(1.5x) + 6(2x) [The hours worked times the pay rate for each period]

Her average income per hour would be:

(40x +3(1.5x) + 6(2x))/49

which we are told is $7/hr.

(40x +3(1.5x) + 6(2x))/49 = 7

40x + 4.5x + 12x = 343

56.5x = 343

x = $6.07/hr

6 0

1 year ago

Which phrase best describes the translation from the graph y=2(x-15)2 +3 to the graph of y=2(x-11)² +3?

Arlecino [84]

Answer: 4 units to the right

Step-by-step explanation:

i took the quiz

5 0

2 years ago