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babymother [125]
3 years ago
7

Which statement is true regarding the graphed functions?

Mathematics
2 answers:
elena55 [62]3 years ago
8 0
The Answer is c I had this question yesterday
Zigmanuir [339]3 years ago
4 0

Answer:

the answer to your question is f(2)=0 and g(-2)=0

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Elliot purchased 3 trick cameras and 4 fake snakes and spent a total of $40. Kaci bought 7 trick cameras and 8 fake snakes, and
ivann1987 [24]

It can be deduced that the price of the trick cameras will be $5 and the price of the snakes will be $6.25.

Based on the information given, the equation to solve the question will be:

3x + 4y = 40 ...... i

7x + 8y = 85 ...... ii

Multiply equation i by 7

Multiply equation ii by 3

21x + 28y = 280

21x + 24y = 255

Subtract the equations

4y = 25

y = 25/4 = 6.25

Since 3x + 4y = 40

3x + 4(6.25) = 40

3x + 25 = 40

3x = 40 - 25.

3x = 15

x = 15/3 = 5

Therefore, the price of the trick cameras will be $5 and the price of the snakes will be $6.25.

Read related link on:

brainly.com/question/25771535

5 0
2 years ago
I don’t get this..please help!
Maslowich

Answer:

OPTION 1

Step-by-step explanation:

You just basically plug in x and y values in all the equations and check if you get the same answer each time.

Option 1 is correct because when you plug in let's say the first coordinates,10 and 4  it does give you 6 which is right.

Or you can test it the other way, just plugging in x values and see if you get the right y value for it shown above in the table.

Hope this helps!

3 0
3 years ago
a shopkeeper buys cocacola 60 rupees a dozen and sell 6 rupees per bottle find his profit or loss persentage​
Lady_Fox [76]

Answer:

20%

Step-by-step explanation:

12 bottle is 60 rupees

each sold 6 ruppes

so 12 bottle cost 72 ruppes

12*100/60 = 20%

8 0
3 years ago
Read 2 more answers
20 POINTS!!!
notka56 [123]

\dfrac{2}{\sqrt3\cos x+\sin x}=\sec\left(\dfrac{\pi}{6}-x\right)\\\\\dfrac{2}{\sqrt3\cos x+\sin x}=\dfrac{1}{\cos\left(\dfrac{\pi}{6}-x\right)}\ \ \ \ \ (*)\\----------------\\\\\cos\left(\dfrac{\pi}{6}-x\right)\ \ \ \ |\text{use}\ \cos(x-y)=\cos x\cos y+\sin x\sin y\\\\=\cos\dfrac{\pi}{6}\cos x+\sin\dfrac{\pi}{6}\sin x=\dfrac{\sqrt3}{2}\cos x+\dfrac{1}{2}\sin x=\dfrac{\sqrt3\cos x+\sin x}{2}\\------------------------------

(*)\\R_s=\sec\left(\dfrac{\pi}{6}-x\right)=\dfrac{1}{\cos\left(\dfrac{\pi}{6}-x\right)}=\dfrac{1}{\dfrac{\sqrt3\cos x+\sin x}{2}}\\\\=\dfrac{2}{\sqrt3\cos x+\sin x}=L_s

6 0
3 years ago
Read 2 more answers
Please help asap!! will give brainlist :)
Naddik [55]

Yo sup??

Area of trapezium=1/2*(sum of opposite sides)*(height of trapezium)

=1/2*(12.5+17.5)*6

=1/2*30*6

=90 cm²

Therefore the correct answer is option A

Hope this helps.

8 0
3 years ago
Read 2 more answers
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