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ICE Princess25 [194]
2 years ago
7

Does this graph show a function?

Mathematics
2 answers:
MaRussiya [10]2 years ago
7 0

Answer:

A. No, the graph fails the vertical line test.

Step-by-step explanation:

First let's see what a vertical test is.

It is a test used to find the whether the given graph is a function or not.

We draw a vertical line on the given graph, if the line cuts the graph at only one point of the graph, then it is a function.

If the line cuts the graph at more than one point, then it is not a function.

So, if we draw a vertical line on the given circle, the vertical line cuts the graph at two points of the graph.

Therefore, it is not a function and it is fails the vertical test.

Answer is A. No, the graph fails the vertical line test.

Herewith I have attached the figure.

Romashka [77]2 years ago
6 0
A, no because it fails the vertical line test
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Write a rule for the nth term of the arithmetic sequence. Then graph the first six terms of the sequence. a6=-12 a12=-36
denis-greek [22]

Answer:

We need to find the first term.  We can use the formula

an = a1 + d(n - 1)

to solve for a1.  We already know the 12th term, a12, common difference, d, and nth sequence, n.

a12 = -36

d = -4

n = 12

-36 = a1 - 4(12 - 1)

-36 = a1 - 44

8 = a1

The first term is 8.  Therefore, your formula is

an = 8 - 4(n - 1)

an = -4n + 12

Then use this formula to graph.

n is the independent variable.

an is the dependent variable.

Your graph will be a line.

n    |       an

___________

1          8

2          4

3          0

4         -4

5         -8

6         -12

Step-by-step explanation:

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3 0
3 years ago
Suppose a regular n-gon is inscribed in a circle of radius r. Diagrams are shown for n=6, n=8, and n = 12. n = 6 n=8 n = 12 a a
m_a_m_a [10]

Answer:If an N-gon (polygon with N sides) has perimeter P, then each of the  

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radians.  (Do you understand radian measure well enough to follow me  

this far?)

The two lines I just drew, plus the side of the polygon between them,  

form an isosceles triangle.  Adding the altitude of the isosceles  

triangle makes two right triangles, and we can use one of them to  

derive the equation

 sin(theta/2) =  s/(2R)

where theta is the apex angle (which I said is 2*pi/N radians), R is  

the length of the lines to the center (the radius of the circumscribed  

circle), and s is the length of the side (which I said is P/N).

Putting those values into the equation, we have

 sin(pi/N) = P/(2NR)

so that

 P = 2NR sin(pi/N)

gives the perimeter of the N-gon with circumradius R.

Can we see a connection between this formula and the perimeter of a  

circle?  The perimeter of the circumcircle is 2*pi*R.  As we increase  

N, the perimeter of the polygon should get closer and closer to this  

value.  Comparing the two, we see

 2NR*sin(pi/N) approaches 2*pi*R

 N*sin(pi/N)   approaches pi

You can check this out with a calculator, using big numbers for N such  

as your teacher's N=1000.  If you calculate the sine of an angle in  

degrees rather than radians, the formula will look like

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Step-by-step explanation:

6 0
3 years ago
What is the value of the expression below when z = 4?<br> 10z - 3
sergey [27]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
The sector of a circle with a 12-inch radius has a central angle measure of 60°. What is the exact area of the sector in terms o
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3 years ago
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Likurg_2 [28]

Answer:

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Step-by-step explanation:

Use the second equation to substitute for y in the first.

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  x -2x +1 + 4x² = 4 . . . . . . . eliminate parentheses

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Now we can rearrange the middle term to ease factoring by grouping.

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  5x(x -1) +3(x -1) = 0

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The values of x that make these factors zero are ...

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The corresponding values of y are ...

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The solutions are: (x, y) = (-3/5, 4/5) or (1, 4).

___

A graphing calculator verifies these solutions.

3 0
3 years ago
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