The total energy used is 1.8 × 10⁻⁶ J
You can calculate the energy stored on a capacitor by using the following equation.
U = CV²
, where C =
<h2>Further Explanation</h2>
If you substitute C in the equation, then you can express the equation as
U = QV
The energy stored in the capacitor = U
The capacitance = C
The Voltage applied or potential differences is = V
<u>From the question: </u>
- The energy stored in the capacitor =?
- The distance between the two flat parallel plates = 1.50 mm
- The Voltage Applied = 200 V
- The magnitude of charge on each plate = 0.0180 μc = 1.80 × 10 ⁻⁸ C
To determine the potential energy of the capacitor, we use the formula
U = ½ QV
U = ½ x 1.80 × 10 ⁻⁸ x 200
U = 1.8 × 10⁻⁶ J
Therefore, the total energy stored 1.8 × 10⁻⁶ J
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KEYWORDS:
- air capacitor
- potential difference
- two parallel plates
- magnitude of charge
- voltage applied