Ask question

Ask question

All categories

3 years ago

10

If a fast-moving car making a loud noise approaches and moves past the person, what will happen as the distance between the two

increases?

1 answer:

Mrac [35]3 years ago

5 0

The Car Will Cause Some Kind Of Wind Wave And Hit The Person's Body But Its Not Harmful And You Will Hear The Loud Noise Passing By

You might be interested in

How would you know if a force is acting on an object?

Artemon [7]

Answer:

microscope

Explanation:

6 0

2 years ago

Read 2 more answers

If a planet has a radius 20% greater than that of the Earth but has the same mass as the Earth, what is the acceleration due to

Vaselesa [24]

Answer:

$g_2=6.8125 m^2/sec$

Explanation:

We know that

Acceleration due to gravity g is given by the formula

$g= \frac{GM}{r^2}$

G= gravitational constant

M= mass of the Earth

r= radius of the earth

$g_1 = GM/r_1^2$

Let acc. due to gravity after radius is 20% greater be g_2

then

$g_2=GM/r_2^2$

=> g1/g2 = (r_2/r_1)^2 => g2 = 9.81/1.2^2 = 6.8125

5 0

2 years ago

Read 2 more answers

for an object that is speeding up in the positive direction, what does the displacement vs. time graph look like?

slava [35]

Answer:

The speeding up is steady, it is a parabola (a=V*t+(at^2)/2), and give it's an equation in connection to time, at that point, it is conceivable to discover the separation recipe by utilizing more substantial amount mathematics(integrals).

Explanation:

7 0

3 years ago

Read 2 more answers

How do I solve the following problem?

lukranit [14]

Use the impulse-momentum theorem.

$Ft = mv$

Substitute your known values:

$(120kg)(20m/s) = F(1.5)

F= 1600N$

Hope this helps!

7 0

3 years ago

Convert 3.5revolutions to radians.

olga55 [171]

As we know that

$1 revolution = 2\pi radian$

now we know that

$3.5 revolution = 3.5 rev\times \frac{2\pi rad}{1 rev}$

$3.5 rev = 21.98 rad$

so it is 21.98 radian

8 0

3 years ago

Read 2 more answers