A thin electrical heating element provides a uniform heat flux qo" to the outer surface of a duct through which air flows. The d
1 answer:
Answer:
a)q= 2800 W/m²
b)To=59.4°C
Explanation:
Given that
L = 10 mm
K= 20 W/m·K
T=30°C
h= 100 W/m²K
Ti=58°C
a)
Heat flux q
q= h ΔT
q= 100 x (58 - 30 )
q= 2800 W/m²
b)
As we know that heat transfer by Fourier law given as
Q= K A ΔT/L
Lets take outer temperature is To
So by Fourier law
To= Ti + qL/K
Now by putting the values
To= Ti + qL/K
To=59.4°C
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Answer:
planet that is farthest away is planet X
kepler's third law
Explanation:
For this exercise we can use Kepler's third law which is an application of Newton's second law to the case of the orbits of the planets
T² = ( a³ = K_s a³
Let's apply this equation to our case
a =
for this particular exercise it is not necessary to reduce the period to seconds
Plant W
10² = K_s
a_w =
a_w = 4.64
Planet X
a_x =
a_x = \frac{1}{ \sqrt[3]{K_s} } 74.3
Planet Y
a_y =
a_y = \frac{1}{ \sqrt[3]{K_s} } 18.6
Planet z
a_z =
a_z = \frac{1}{ \sqrt[3]{K_s} } 41.8
From the previous results we see that planet that is farthest away is planet X
where we have used kepler's third law
It depends on what is the reference frame where the velocity of the leaf (6 m/s) is measured.
If it is measured with respect to the creek, then the answer is simply "6 m/s south".
If it is measured with respect to the observer moving toward the leaf, then the velocity of the leaf relative to the ground is actually the sum between the velocity of the leaf relative to the observer (6 m/s south, so 6 m/s) and the velocity of the observer relative to the ground (2 m/s north, so -2 m/s):
and the direction is south.