Answer:
The point C is 12.68 km away from the point A on a bearing of S23.23°W.
Step-by-step explanation:
Given that AB is 50 km and BC is 40 km as shown in the figure.
From the figure, the length of x-component of AC = |AB sin 80° - BC cos 20°|
=|50 sin 80° - 40 cos 20°|=11.65 km
The length of y-component of AC = |AB cos 80° - BC sin 20°|
=|50 cos 80° - 40 sin 20°|= 5 km
tan
= 5/11.65
=23.23°
AC= 
km
Hence, the point C is 12.68 km away from the point A on a bearing of S23.23°W.
The radius is 4.99, im sure
Answer:
The sin A expressed in ratio form is 
Step-by-step explanation:
From the given right angled triangle diagram, sin A is calculated as follows;
Therefore, the sin A expressed in ratio form is
Answer:
The rock splashes down when h(t) = 0. Set h(t) = 0 and solve for t using quadratic formula.
0 = − 4.9t^2 + 178t + 325
t = 38.07, -1.74
(Throw away the negative answer, since time can't be negative.)
t = 38.07 sec
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