Answer:
choice 4
triangle ABC is congruent to triangle DCB because of the Side-Side-Side congruency theorem
Step-by-step explanation:
Answer:
The correct answer has already been given (twice). I'd like to present two solutions that expand on (and explain more completely) the reasoning of the ones already given.
One is using the hypergeometric distribution, which is meant exactly for the type of problem you describe (sampling without replacement):
P(X=k)=(Kk)(N−Kn−k)(Nn)
where N is the total number of cards in the deck, K is the total number of ace cards in the deck, k is the number of ace cards you intend to select, and n is the number of cards overall that you intend to select.
P(X=2)=(42)(480)(522)
P(X=2)=61326=1221
In essence, this would give you the number of possible combinations of drawing two of the four ace cards in the deck (6, already enumerated by Ravish) over the number of possible combinations of drawing any two cards out of the 52 in the deck (1326). This is the way Ravish chose to solve the problem.
Another way is using simple probabilities and combinations:
P(X=2)=(4C1∗152)∗(3C1∗151)
P(X=2)=452∗351=1221
The chance of picking an ace for the first time (same as the chance of picking any card for the first time) is 1/52, multiplied by the number of ways you can pick one of the four aces in the deck, 4C1. This probability is multiplied by the probability of picking a card for the second time (1/51) times the number of ways to get one of the three remaining aces (3C1). This is the way Larry chose to solve the this.
Step-by-step explanation:
We separate equation by looking at x and y projection separately.
Let us look at the x projection first.
Motion starts with initial velocity
because there is no force acting along the x-axis we don't have any acceleration along the x-axis. Our equation would be:
Now our y equation will be a little bit more complicated. There is gravity working against our projectile and we also have to take into effect the hight from which the projectile is launched.
With all that in mind let us write the equation for y projection:
The term
represents gravity and as you can see it is negative, which means gravity is pulling our projectile down.
There is one more thing we can do. We can express initial velocity
in relation to circular motion used to launch the projectile.
Where r is the length of the letter used to launch the projectile, and
is angular velocity.
If we combine our x and y equations we can get the trajectory of our projectile.
This is the equation of a parabola. If you follow this link(https://www.desmos.com/calculator/vogcuygjhs) it will take to an interactive graph where you can see how trajectory looks like depending on some of the paramaters.
Answer:
J
Step-by-step explanation:
prob of landing 4 x prob of landing move back
1/4 x 1/3 = 1/12
Hi!
The least common denominator is : B. 42.
9/14=27/42
and
2/21=4/42