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Thepotemich [5.8K]
3 years ago
15

7 cos x+1=6 secx solve for x

Mathematics
1 answer:
jonny [76]3 years ago
6 0
7cos(x) + 1 = 6sec(x)
7cos(x) + 1 = 6/cos(x)
7cos^(x) + cos(x) = 6
7cos^(x) + cos(x) - 6 = 0
[7cos(x) - 6][cos(x) + 1] = 0
cos(x) = 6/7 , x = arccos(6/7) and
cos(x) = -1, x = 180
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4n² + 3n +5 and 2n²+3​
joja [24]

Answer:

6n^2+3n+8

Step-by-step explanation:

simplify like terms. keep the exponent the same degree it started as

6 0
3 years ago
What is 15267 times 16459 then divide by 7? ​
lesya [120]

Answer:

33297327

Step-by-step explanation:

(15267 * 15267) ÷ 7

= 15267 * 15267

= 233081289 ÷ 7

= 33297327

Hope this helps! :)

7 0
2 years ago
The roots of 2x^2-3x=4 are a and b. Find the simplest quadratic equation which has roots 1/a and 1/b
Tju [1.3M]
Find the roots

solve
we use hmm, completing the suare
2(x²-1.5x)=4
divide both sides by 2
x²-1.5x=2
take 1/2 of linear coeiftn and square it
-1.5/2=-0.75, (-0.75)²=0.5625
add that to both sides
x²-1.5x+0.5625=2+0.5625
factor perfect squaer trinomial
(x-0.75)²=2.5625
square root both sides, remember to take positive and negative square roots
x-0.75=+/-√2.5625
add 0.75 to both sides
x=0.75+/-√2.5625

the roots are x=0.75+√2.5625 and x=0.75-√2.5625

1/a and 1/b
1/(0.75+√2.5625) and 1/(0.75-√2.5625)

if the roots of a quadratic equation are r1 and r2 then it factors to
(x-r1)(x-r2)
so then we can factor our equation to be
(x-\frac{1}{0.75+\sqrt{2.5625}})(x-\frac{1}{0.75-\sqrt{2.5625}})

if we were to try and expand it, we would get
x²+0.75x-0.5
that's the simpliest equation with roots 1/a and 1/b where a and b are he roots of 2x²-3x=4


x²+0.75x-0.5 is answer
8 0
3 years ago
Joe works as a busboy making $7 per hour and as a theater usher making $9 per hour. Let b be the number of hours he works as a b
Vilka [71]

Answer:

The inequality describing the situation is:

7b+9u>1500

Step-by-step explanation:

Joe works as a busboy at the rate of = $7 per hour

Let the number of hours he works as a bus boy this month be = b hours

∴ Amount Joe would make this month working as a busboy =\$7\times b=\$7b

Joe works as a theater usher at the rate of = $9 per hour

Let the number of hours he works as a theater usher this month be = u hours

∴ Amount Joe would make this month working as a theater usher =\$9\times u=\$9u

Total amount Joe would make this month =\$(7b+9u)

His goal is earn more than $1500 this month.

∴ The situation can be represented in the following inequality:

7b+9u>1500

6 0
3 years ago
HELP ASAP PLEASE & SHOW UR WORK!! THANK YOU <3
olchik [2.2K]

Answer:

x^2 - 5x = 14

x^2 - 5x-14 = 0

Now, we have to find the multiples of -14 and numbers that add/subtract to -5; this helps to find the factors.

-7+2 = -5

-7*2 = -14

Based on the above info, we can find out my factors; they are:-

(x-7)(x+2)

4 0
3 years ago
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