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Evgesh-ka [11]
3 years ago
14

Evaluate 12C4 and 11P4

Mathematics
1 answer:
il63 [147K]3 years ago
7 0
12P4: 11•5•9=495
11P4: 11 •10•9•8=7920
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Your friend shows you a coin collection. In it 45/50 of the coins are quarters. what percent of the coins are quarters?
Ksenya-84 [330]

Answer:

90% of them are quarters.

Step-by-step explanation:

If you take 50 and multiply it by two, you get 100. But, in order to get the right number, you have to multiply 45 by two as well. 45 x 2 is 90. 90 out of 100 is 90 percent. So 90% is the answer.

8 0
3 years ago
Read 2 more answers
I have k quarters, five less quarters than nickels and one more than twice as many dimes as quarters. Find the value of the coin
Alenkinab [10]

Answer:

(35k + 20) cents

Step-by-step explanation:

First of all, let us have the value of each unit:

1 quarter = 25 cents

1 nickel = 5 cents

1 dime = 10 cents

Given that number of quarter = k

Quarters are 5 lesser than Nickels, so number of nickels = k+5

One more than twice as many dimes as quarters:

k = 2 \times Number of Dimes + 1

So, number of dimes = \frac{1}{2}(k-1)

Value of quarters = 25 \times k cents

Value of nickels = 5 \times (k+5) = (5k+25)\ cents

Value of dimes = \frac{1}{2}(k-1) \times 10 = (5k-5)\ cents

So, total value of coins =

25k + 5k +25 +5k-5\\\Rightarrow (35k+20)\ cents

5 0
3 years ago
Read 2 more answers
Please help me in this questions....​
Ivahew [28]

Part (i)

I'm going to use the notation T(n) instead of T_n

To find the first term, we plug in n = 1

T(n) = 2 - 3n

T(1) = 2 - 3(1)

T(1) = -1

The first term is -1

Repeat for n = 2 to find the second term

T(n) = 2 - 3n

T(2) = 2 - 3(2)

T(2) = -4

The second term is -4

<h3>Answers: -1, -4</h3>

==============================================

Part (ii)

Plug in T(n) = -61 and solve for n

T(n) = 2 - 3n

-61 = 2 - 3n

-61-2 = -3n

-63 = -3n

-3n = -63

n = -63/(-3)

n = 21

Note that plugging in n = 21 leads to T(21) = -61, similar to how we computed the items back in part (i).

<h3>Answer:  21st term</h3>

===============================================

Part (iii)

We're given that T(n) = 2 - 3n

Let's compute T(2n). We do so by replacing every copy of n with 2n like so

T(n) = 2 - 3n

T(2n) = 2 - 3(2n)

T(2n) = 2 - 6n

Now subtract T(2n) from T(n)

T(n) - T(2n) = (2-3n) - (2-6n)

T(n) - T(2n) = 2-3n - 2+6n

T(n) - T(2n) = 3n

Then set this equal to 24 and solve for n

T(n) - T(2n) = 24

3n = 24

n = 24/3

n = 8

This means 2n = 2*8 = 16. So subtracting T(8) - T(16) will get us 24.

<h3>Answer: 8</h3>
4 0
3 years ago
-3/4 + 1/5 find each sum with out using a number line
Maru [420]
Might be terribly wrong since it's been a while that I've done fractions, but I got -11/20. Hope this helps!!!
8 0
3 years ago
20 POINTS PLS FAST
Sati [7]

Answer:

d

Step-by-step explanation:

i think its d

5 0
3 years ago
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