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irina [24]
4 years ago
8

What is the solution of |2x + 3| = 3x + 5?

Mathematics
2 answers:
Elanso [62]4 years ago
5 0

Answer:

x=-\frac{8}{5}

Step-by-step explanation:

The given absolute value equation is

|2x+3|=3x+5

This implies that;

-(2x+3)=3x+5\:or\:2x+3=3x+5

-2x-3=3x+5\:or\:2x+3=3x+5

Group similar terms in both equations;

-2x-3x=5+3\:or\:2x-3x=5-3

-5x=8\:or\:-x=-2

x=-\frac{8}{5}\:or\:x=2

CHECK

|2(2)+3|=3(2)+5

|4+3|=6+5

7=11.

This false. Hence  x=2 is an extraneous solution.

When x=-\frac{8}{5}

|2(-\frac{8}{5})+3|=3(-\frac{8}{5})+5

|-\frac{16}{5}+3|=(-\frac{24}{5})+5

|-\frac{1}{5}|=\frac{1}{5}

\frac{1}{5}=\frac{1}{5}

This statement is true

tekilochka [14]4 years ago
4 0
<h2>Answer:</h2>

<u>The right answer is </u><u>x = -8/5</u>

<h2>Step-by-step explanation:</h2>

See the attached figure

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garri49 [273]

Answer:

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Step-by-step explanation:

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CP || GR

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\angle BCG \cong \angle BPE  (Alternate \: \angle 's) \\\angle GBC \cong \angle EBP  (Vertical \: \angle 's) \\\therefore \triangle BCG \sim \triangle BPE  (AA \: postulate) \\\\\therefore \frac{BE}{BG}  =\frac{PE}{GC} =\frac{BP}{BC}...(csst)\\\\\therefore \frac{BE}{425}  =\frac{PE}{375} =\frac{225}{325}\\\\\therefore \frac{BE}{425}  =\frac{PE}{375} =\frac{9}{13}\\\\\therefore \frac{BE}{425} =\frac{9}{13}\\\\BE =\frac{9\times 425}{13}\\\\BE =\frac{3,825}{13}\\\\BE = 294.23\: ft \\\\\&\\\frac{PE}{375} =\frac{9}{13}\\\\PE =\frac{9\times 325}{13}\\\\PE =\frac{3,375}{13}\\\\PE = 259.615385 \\\\PE = 259.62 \: ft\\\\

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