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irina [24]
3 years ago
8

What is the solution of |2x + 3| = 3x + 5?

Mathematics
2 answers:
Elanso [62]3 years ago
5 0

Answer:

x=-\frac{8}{5}

Step-by-step explanation:

The given absolute value equation is

|2x+3|=3x+5

This implies that;

-(2x+3)=3x+5\:or\:2x+3=3x+5

-2x-3=3x+5\:or\:2x+3=3x+5

Group similar terms in both equations;

-2x-3x=5+3\:or\:2x-3x=5-3

-5x=8\:or\:-x=-2

x=-\frac{8}{5}\:or\:x=2

CHECK

|2(2)+3|=3(2)+5

|4+3|=6+5

7=11.

This false. Hence  x=2 is an extraneous solution.

When x=-\frac{8}{5}

|2(-\frac{8}{5})+3|=3(-\frac{8}{5})+5

|-\frac{16}{5}+3|=(-\frac{24}{5})+5

|-\frac{1}{5}|=\frac{1}{5}

\frac{1}{5}=\frac{1}{5}

This statement is true

tekilochka [14]3 years ago
4 0
<h2>Answer:</h2>

<u>The right answer is </u><u>x = -8/5</u>

<h2>Step-by-step explanation:</h2>

See the attached figure

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Let C be the curve of intersection of the parabolic cylinder x^2 = 2y, and the surface 3z = xy. Find the exact length of C from
Maslowich
I've attached a plot of the intersection (highlighted in red) between the parabolic cylinder (orange) and the hyperbolic paraboloid (blue).

The arc length can be computed with a line integral, but first we'll need a parameterization for C. This is easy enough to do. First fix any one variable. For convenience, choose x.

Now, x^2=2y\implies y=\dfrac{x^2}2, and 3z=xy\implies z=\dfrac{x^3}6. The intersection is thus parameterized by the vector-valued function

\mathbf r(x)=\left\langle x,\dfrac{x^2}2,\dfrac{x^3}6\right\rangle

where 0\le x\le 4. The arc length is computed with the integral

\displaystyle\int_C\mathrm dS=\int_0^4\|\mathbf r'(x)\|\,\mathrm dx=\int_0^4\sqrt{x^2+\dfrac{x^4}4+\dfrac{x^6}{36}}\,\mathrm dx

Some rewriting:

\sqrt{x^2+\dfrac{x^4}4+\dfrac{x^6}{36}}=\sqrt{\dfrac{x^2}{36}}\sqrt{x^4+9x^2+36}=\dfrac x6\sqrt{x^4+9x^2+36}

Complete the square to get

x^4+9x^2+36=\left(x^2+\dfrac92\right)^2+\dfrac{63}4

So in the integral, you can substitute y=x^2+\dfrac92 to get

\displaystyle\frac16\int_0^4x\sqrt{\left(x^2+\frac92\right)^2+\frac{63}4}\,\mathrm dx=\frac1{12}\int_{9/2}^{41/2}\sqrt{y^2+\frac{63}4}\,\mathrm dy

Next substitute y=\dfrac{\sqrt{63}}2\tan z, so that the integral becomes

\displaystyle\frac1{12}\int_{9/2}^{41/2}\sqrt{y^2+\frac{63}4}\,\mathrm dy=\frac{21}{16}\int_{\arctan(3/\sqrt7)}^{\arctan(41/(3\sqrt7))}\sec^3z\,\mathrm dz

This is a fairly standard integral (it even has its own Wiki page, if you're not familiar with the derivation):

\displaystyle\int\sec^3z\,\mathrm dz=\frac12\sec z\tan z+\frac12\ln|\sec x+\tan x|+C

So the arc length is

\displaystyle\frac{21}{32}\left(\sec z\tan z+\ln|\sec x+\tan x|\right)\bigg|_{z=\arctan(3/\sqrt7)}^{z=\arctan(41/(3\sqrt7))}=\frac{21}{32}\ln\left(\frac{41+4\sqrt{109}}{21}\right)+\frac{41\sqrt{109}}{24}-\frac98

4 0
4 years ago
What does 14+3n=14 equal to?
Katen [24]

Answer:

n=0

Step-by-step explanation:

14+3(0)=14

:) :) :)

3 0
3 years ago
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tekilochka [14]

Answer:

If the equation is actually typed like that the answer will be

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If is typed like this 3-2x-3+3=

It will be

-2x+3

4 0
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