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Lana71 [14]
3 years ago
14

Name the minor arc and find its measure.

Mathematics
1 answer:
CaHeK987 [17]3 years ago
8 0
The problem ask to find and choose the correct choice in the following choices that states the name of the minor arc and its measure base on the given date in your diagram. The answer would be letter D. arc AB;174 degree. I hope you are satisfied with my answer 
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A square piece of paper has an area of x2 square units. A
Dmitry_Shevchenko [17]

Answer:

Length of rectangular strip = 12

area of rectangular strip =   2*12 = 24

Area of square =  x^2 = 12^2 = 144

Step-by-step explanation:

Area of square x^2

area of rectangle is given by length * width

Length of rectangular strip = x

width of rectangular strip = 2

area of rectangular strip =  length * width = 2*x = 2x

Area of square piece of paper when  rectangular strip is taken away from it

= Area of square - area of rectangular strip

= x^2 -2x

It is given that Area of square piece of paper when  rectangular strip is taken away from it is 120 square units.

Thus,

x^2 -2x = 120\\=> x^2 -2x -120 = 0\\=> x^2 -12x +10x-120\\=> x(x-12) +10(x-12)\\=> (x+10)(x-12) = 0\\\\

Thus,

either x+10 = 0 or x -12= 0

x = -10 or x = 12

but length cannot  be negative hence neglecting x = -10

hence value of x is 12.

Hence,

Length of rectangular strip = 12

area of rectangular strip =   2*12 = 24

Area of square =  x^2 = 12^2 = 144

5 0
3 years ago
If x=-3, then the solution of the equation 2x+6 is ?
Vlada [557]

Hello!

if x = -3, just substitute it for x (replace the x with -3)

2(-3) + 6 = 0

2 * -3 = -6

-6 + 6 = 0

I hope this helps, and have a nice day!

6 0
3 years ago
Which expressions can never result in a negative real number when evaluated for any value of x? Select all that apply.
kolezko [41]
It is 5 beacause the x^1/3
7 0
3 years ago
Simplify the following radicals. 1. √16 2. √17 3. √18 4. √19 5. √20
Pavel [41]

Answer:

Step-by-step explanation:

1) \sqrt{16}= \sqrt{4*4}=4\\\\\\2)  \sqrt{17}

This is the simplest form as 17 is a prime number.

3)  \sqrt{18}= \sqrt{2*3*3} = 3 \sqrt{2}\\\\\\4) \sqrt{19}

19 is a prime number. so it is the simplest form.

5)  \sqrt{20}= \sqrt{2*2*5}=2 \sqrt{5}

3 0
3 years ago
Can someone please help me with these problems i’d really appreciate it! :)
shepuryov [24]

1. Reflect over x axis, right 1, up 8

2. Ref. over x, stretch 4 (up and down), up 6

3. Stretch 2 (side to side), left 9, down 5

4. stretch 8 ( s to s), reflect over y, down 4

5. Ref. over x, stretch 2/7 (s to s), up 5

7 0
3 years ago
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