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Alex777 [14]
4 years ago
14

Evaluate the logarithmic expression log6 1

Mathematics
1 answer:
AlekseyPX4 years ago
3 0

Answer:

Logarithm base  6  of  1  is<u>  0</u>.

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Answer:

The given expression  (\frac{5}{6} a^{9}p^{5})  ^{3} = \frac{125}{216}  \times a^{(27) } \times p^{(15)}

Step-by-step explanation:

Here, the given expression is:  (\frac{5}{6} a^{9}p^{5})  ^{3}

Now, starting from the outer most bracket.

As we know :

(abc)^{n}   = (a)^{n} \times (b)^{n}  \times (c)^{n}

and (a^m)^{n} = a^{(m \times n)}

⇒ (\frac{5}{6} a^{9}p^{5})  ^{3} = (\frac{5}{6})^{3} \times (a^{9})^{3}   \times (p^{5}) ^{3}\\

=\frac{125}{216}  \times (a)^{(9\times3) } \times (p)^{(5 \times 3)}\\= \frac{125}{216}  \times a^{(27) } \times p^{(15)}

Hence, the given expression  (\frac{5}{6} a^{9}p^{5})  ^{3} = \frac{125}{216}  \times a^{(27) } \times p^{(15)}

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With even just two points, you can find the equation of a line in slope-intercept form.

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The equation to solve for the slope is m=\frac{y_2-y_1}{x_2-x_1} when the two points are (x_1,y_1) and (x_2,y_2). Plug the coordinates of these points into the equation and solve for m.

Then, plug m into y=mx+b.

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Then, take any of the given points and plug it into y=mx+b along with the slope. Isolate b to get the y-intercept. Then, plug both m and b back into y=mx+b to get your final equation.

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