Solve the inequality. x – 1 ≤ – 9
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Answer:
Ther has been an increase in the selling time.
Step-by-step explanation:
Step 1. Specify the null hypotesis
In this case, we have to demonstrate that the selling time is now different than before the drought.
Step 2. Choose a significance level
In this problem, is 0.10
Step 3. Compute the mean
In this case, the mean of the sample is 94.
Step 4. Compute the probability value (p) of obtaining a difference between the mean of the sample and the hypothesided value of μ.
The degrees of freedom are calculated as (N-1) = (100-1) = 99. Then we can look up in the t-table (http://davidmlane.com/hyperstat/t-table.html) to calculate the probability value of a t of 1.818 with 99 degrees of freedom. The value of this probability is 0.05.
Step 5. Compare the P-value (0.05) with the significance level (0.10). Since the P-value is less than the significance level, the effect is significant.
Since the effect is significant, the null hypotesis is rejected.
It is concluded that the mean of the selling time has changed (increase) from its previous value.
Okay so first we need to find how many days are in March and February. March has 31 days and because this year was a leap year February has 29 days.
The next step is to convert days to hours.
March: 31x24=744
February: 29x24=696
Now its time to graph
The next step is to convert days to hours.
March: 31x24=744
February: 29x24=696
Now its time to graph