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3 years ago

For the data below what is the outlier? 46, 39, 61, 38, 50, 65, 60, 45, 64, 55

Mathematics

2 answers:

Lubov Fominskaja [6]3 years ago

8 0

The first 3 choices are not outliers, so the answer is D.

vampirchik [111]3 years ago

4 0

Hello there.

<span>For the data below what is the outlier? 46, 39, 61, 38, 50, 65, 60, 45, 64, 55

</span>D. There are no outliers.

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43.77 as a mixed number in simplest form

valina [46]

First you have to take the whole number (43) and then take the decimal and put it over 100 (77/100).

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2 years ago

What is the common ratio of these numbers written as a fraction <br> 768,480,300,187.5

kolbaska11 [484]

Answer:

Step-by-step explanation:

im pretty sure it is 768/187.5 = about 4

because you are taking the highest number and putting it over the lowest number

4 0

3 years ago

Two different radioactive isotopes decay to 10% of their respective original amounts. Isotope A does this in 33 days, while isot

Andrews [41]

Answer:

The approximate difference in the half-lives of the isotopes is 66 days.

Step-by-step explanation:

The decay of an isotope is represented by the following differential equation:

$\frac{dm}{dt} = -\frac{t}{\tau}$

Where:

$m$ - Current mass of the isotope, measured in kilograms.

$t$ - Time, measured in days.

$\tau$ - Time constant, measured in days.

The solution of the differential equation is:

$m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }$

Where $m_{o}$ is the initial mass of the isotope, measure in kilograms.

Now, the time constant is cleared:

$\ln \frac{m(t)}{m_{o}} = -\frac{t}{\tau}$

$\tau = -\frac{t}{\ln \frac{m(t)}{m_{o}} }$

The half-life of a isotope ( $t_{1/2}$ ) as a function of time constant is:

$t_{1/2} = \tau \cdot \ln2$

$t_{1/2} = -\left(\frac{t}{\ln\frac{m(t)}{m_{o}} }\right) \cdot \ln 2$

The half-life difference between isotope B and isotope A is:

$\Delta t_{1/2} = \left| -\left(\frac{t_{A}}{\ln \frac{m_{A}(t)}{m_{o,A}} } \right)\cdot \ln 2+\left(\frac{t_{B}}{\ln \frac{m_{B}(t)}{m_{o,B}} } \right)\cdot \ln 2\right|$

If $\frac{m_{A}(t)}{m_{o,A}} = \frac{m_{B}(t)}{m_{o,B}} = 0.9$ , $t_{A} = 33\,days$ and $t_{B} = 43\,days$ , the difference in the half-lives of the isotopes is: