Answer:
5.62
Step-by-step explanation:
8x-3y=36
8x-3×3=36
8x=36+9
x=5.62
Answer:
- width -- 10 ft
- length -- 35 ft
Step-by-step explanation:
We can let x represent the width. Then the length will be represented by (3x+5), a value 5 more than 3 times the width.
The area is the product of length and width, so is ...
A = (3x +5)(x) = 3x^2 +5x
To make the area 350, we can find the value of x from ...
3x^2 +5x = 350
This can be solved a number of ways. One of them is "completing the square".
3(x^2 +5/3x) = 350
We choose to divide by 3 and add the square of half the x-coefficient.
x^2 +5/3x +(5/6)^2 = (350/3) + (5/6)^2
(x +5/6)^2 = 4225/36 . . . . simplify
x +5/6 = ±√(4225/36) = ±10 5/6 . . . . take the square root
x = 10 or -11 2/3 . . . . subtract 5/6
The positive solution is the one of interest: x = 10.
The driveway is 10 ft wide and 35 ft long.
To create an area that is 1.5 m^2 in size, you will need to make use of a total of 27 triangles.
<h3>How many triangles are needed to compose a region that is 1.5 square meters?</h3>
A square that has a size of one square meter is divided into nine smaller squares that are similar to each other. Each of the little squares is divided into two triangles that are similar to one another.
There are nine smaller squares contained inside one square meter, since 1 square meter may be broken down into nine identical smaller squares. Each of the little squares is divided into two triangles that are similar to one another. 9 smaller squares may be broken down into the following:
9*2=18 (shows identical triangles)
Hence, 1 square meter is decomposed into 18 identical triangles.
We need to find the number of triangles needed to compose a region that is square meters
where
m^2 = 1.5 m^2
Where
1 m^2 = 18 identical triangles.
1.5 m^2 = 1.5 * 18
1.5 m^2 = 27 identical triangles.
In conclusion, To create an area that is 1.5 m^2 in size, you will need to make use of a total of 27 triangles.
Read more about the area
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Answer:
Reflection over y-axis.
Step-by-step explanation:
The transformation being described is a reflection across the y-axis since we would have to flip the signs of the x-values to transform the function. See pictures below.
Hope this helps.
Line segments J'K' and M'N' do not intersect and are the same distance apart as JK and MN.
