Question

A cat had a litter of 5 kittens. If each sex is equally likely, what is the probability that 3 or less were female kittens?

Answer 1

Answer:

0.8125

Step-by-step explanation:

In this question, we are tasked with calculating the probability that 3 or less of her kittens were female.

Since each bsex is of likely probability, the probability of a male kitten = probability of a female kitten = 0.5

Now to calculate for 3 or less female kitten we are calcualting P(f) ≤ 3

In each case, we use the Bernoulli approximation

P(f) ≤ 3 = $5C3 m^{2} f^{3} + 5C2 m^{2} f^{3} + 5C1 m^{4} f + 5C0 m^{5} f^{0}$

Where m is the probability of a male kitten and f is the probability of having a female kitten with both values = 0.5

P(f) ≤ 3 =(0.3125) + (0.3125) + (0.15625) + (0.03125) = 0.8125