1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
emmainna [20.7K]
3 years ago
7

Given no monthly adjustments were made during the year, the December 31 year-end adjusting entry to record the interest on a $10

0,000, 12% bond that pays interest annually on November 1 and was sold at par value will include ______.
Business
1 answer:
beks73 [17]3 years ago
5 0

Answer:

Dr Interest Expense account 10,000

Cr Cash account 10,000

Explanation:

We have to calculate how much interest did the company paid = $100,000 x 10/12 x 12% = $10,000

Then we must record the journal entries

  • Dr Interest Expense account 10,000
  • Cr Cash account 10,000

Since cash is an asset and it decreases, then it should be credited.

Since interest is an expense and it increases, it should be debited.

You might be interested in
Jean is contemplating opening her new small business called Jean’s Gems. She realizes that the first step in beginning her new b
ivann1987 [24]

Answer:

Having a good business idea and market research would make it crystal clear whether or not the project is viable or not. The first thing is that Jean must consider is that he must analze whether the project is financially viable or not. Once we are sure that the return is above the market average thereafter then Jean must consider writing the business proposal.

In business proposal Jean must present his innovation, market research, customer segments, entrepreneur ecosystem in which the business would operate. The marketing strategy, sales forecasting on well researched market research which provides solid grounds for forecasting, future targets, etc. So these all things must be considered while writing. I have prepared a business proposal and worked as a market researcher for that business proposal, traveled 300km for gathering market research. Paper work is nothing in startup. Everything is your market research, understanding your customers, competitors and costs that are associated with the products that we are going to offer.

I will also like to tell that commitment brings money. If you are committed to do a particular thing then be committed but you must analyze the situation first (market research, investment appraisal). Funds are limitless to committed poeples. US startup loans, accelerators programs, etc. There are millions of sources of finance options. We are not in 19 hundred, we are in a modern world and we can arrange money for an attractive investment.

3 0
3 years ago
Arn.hawkeslearning.com/portal/test/testtaketesti 00:28:59 question 23 of 29 step 1 of 2 mary ann has recently inherited $5100. w
Irina18 [472]

Mary Ann will prefer Account 1

The use of "Compounding interest rate," which involves adding interest to the deposit's principal amount, is the main topic of discussion here.

Mary Ann's balance from account 2 over 3.7 years is $6,261.37

The below calculation is to derive maturity and value when an annual rate of 5.5% is applied.

Principal = $5,100

Annual rate = 5.5% semi-annually for 1 years

A = P(1+r/m)^n*t where n=1, t=2

A = 5,400*(1 + 0.031/2)^1*2

A = 5,400*(1.0155)^2

A = 5,400*1.03124025

A = 5568.69735

A = $5,568.70.

In conclusion, the accrued value she will get years one year for this account is $5,568.70,

When the amount compounds continuously at a rate of 3.4% per year, the maturity value is determined by the calculation below.

Principal = $5,400

Annual rate = 3.4% continuously

A = P.e^rt where n=1

A = 5,400 * e^(0.04*1)

A = 5,400 * 1.04081077419

A = 5620.378180626

A = $5,620.39.

In conclusion, the accrued value she will greater one year for this account is $5,620.39.

Referring to how much would Mary Ann's balance be from Account 2 over 3.7 years. It is calculated as follows:

Annual rate = 3.4% continuously

A = P.e^rt where n=3.7

A = 5,400 * e^(0.04*3.7)

A = 5,400 * e^0.148

A = 5,400 * 1.15951289636

A = 6261.369640344

A = $6,261.37

Therefore, the accrued value she will get after 3.7 years for this account is $6,261.37

Learn more about the Annual rate here

brainly.com/question/14170671

#SPJ4

3 0
2 years ago
The Duerr Company manufactures a single product. All raw materials used are traceable to specific units of product. Current info
Gemiola [76]

Answer:

Direct material used= $102,000

Cost of goods manufactured= $327,000

COGS= $347,000

Explanation:

<u>First, we need to calculate the cost of direct material used:</u>

Direct material used= beginning inventory + purchases - ending inventory

Direct material used= 28,000 + 105,000 - 31,000

Direct material used= $102,000

<u>Now, the cost of goods manufactured:</u>

cost of goods manufactured= beginning WIP + direct materials used + direct labor + allocated manufacturing overhead - Ending WIP

cost of goods manufactured= 40,000 + 102,000 + 130,000 + 105,000 - 50,000

cost of goods manufactured= $327,000

<u>Finally, the cost of goods sold:</u>

COGS= beginning finished inventory + cost of goods manufactured - ending finished inventory

COGS= 80,000 + 327,000 - 60,000

COGS= $347,000

6 0
3 years ago
The new Fore and Aft Marina is to be located on the Ohio River near Madison, Indiana. Assume that Fore and Aft decides to build
Nataly [62]

Po = 0.5385, Lq = 0.0593 boats, Wq = 0.5930 minutes, W = 6.5930 minutes.

<u>Explanation:</u>

The problem is that of Multiple-server Queuing Model.

Number of servers, M = 2.

Arrival rate, \lambda= 6 boats per hour.

Service rate, \mu= 10 boats per hour.

Probability of zero boats in the system,\mathrm{PO}=1 /\{[(1 / 0 !) \times(6 / 10) 0+(1 / 1 !) \times(6 / 10) 1]+[(6 / 10) 2 /(2 ! \times(1-(6 /(2 \times 10)))]\} = 0.5385

<u>Average number of boats waiting in line for service:</u>

Lq =[\lambda.\mu.( \lambda / \mu )M / {(M – 1)! (M. \mu – \lambda )2}] x P0

= [\{6 \times 10 \times(6 / 10) 2\} /\{(2-1) ! \times((2 \times 10)-6) 2\}] \times 0.5385 = 0.0593 boats.

The average time a boat will spend waiting for service, Wq  =  0.0593 divide by 6 = 0.009883 hours = 0.5930 minutes.

The average time a boat will spend at the dock, W =  0.009883 plus (1 divide 10) = 0.109883 hours = 6.5930 minutes.

4 0
3 years ago
Granite works maintains a debt-equity ratio of .65 and has a tax rate of 21 percent. the pretax cost of debt is 9.8 percent. the
siniylev [52]
<span>9.20 percent

Re= 0.036 +1.2(0.085) = 0.138
Re= [($1.10 x 1.02)$19] +.02 = 0.0790526

ReAverage = (0.138 + 0.0790526)/2 = 0.108526

WACC = (1/1.65)(0.108526) + (0.65/1.65)(0.098)(1-0.32) = 9.20 percent</span>
4 0
3 years ago
Other questions:
  • Which of the following is an example of a fixed expense.
    8·1 answer
  • On January 1, ABC started the year with a $400,000 balance in Retained Earnings and a $550,000 balance in Common Stock. During t
    10·1 answer
  • What is the best way to deal with conflict in the workplace?​
    6·2 answers
  • You believe your restaurant concept can generate $50,000 in net profit per year. Your investors demand at 20% return on investme
    11·1 answer
  • The Daily Grind sells coffee makers. Its inventory of coffee makers without timers cost $20,000 and has a net realizable value o
    10·1 answer
  • What is the tribal assistance coordination group (TAC-G)?
    15·1 answer
  • what song says "what doesn't kill you, makes you ugly. life gives you lemons at least it gives you something." if you don't know
    10·2 answers
  • Type the correct answer in the box. Spell all words correctly. While executing a project, it is important to express mutual_____
    12·1 answer
  • Perit Industries has $165,000 to invest. The company is trying to decide between two alternative uses of the funds. The alternat
    6·1 answer
  • Under normal conditions, air management increases your work time, but if you are lost or trapped, it:_______
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!