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GREYUIT [131]
3 years ago
10

10 pens cost £6.50. Find the cost of 4 pens

Mathematics
1 answer:
Setler [38]3 years ago
3 0
10 pens=£6.50
1 pen=£0.65
4 pens=£0.65×4
4 pens=£2.6
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Mark rolls 2 fair dice and adds the results from each.
Natali5045456 [20]

Answer:

P ( X > 5 ) = 72,2 %

Step-by-step explanation:

The probability of success ( outcomes bigger than 5 )

If dice  1  outcome is 6 no matter wich outcome we get from dice 2 all events are successful, the we have 6 outcomes

If dice 1 outcome is 5  we also have  6 outcomes

If dice 1  outcomes is 4 we have 5 positive outcomes

If dice 1  outcome is 3  we have 4 positive outcomes

If dice 1  outcome is 2  we have 3 positive outcomes

if dice 1  outcome is 1  we have 2 positive outcomes

Total evaluating dice 1: positive outcomes 26

We will get the sames results analysing  dice 2 then we have a total of

52 successful events

And total numbers of outcomes is 36 + 36 = 72

Then

P ( X > 5 ) = 52/72  

P ( X > 5 ) = 0,722    

P ( X > 5 ) = 72,2 %

7 0
3 years ago
Can a polynomial have a zero as a term
Mnenie [13.5K]

Answer:

No

Step-by-step explanation:

polynomial does not have any zero terms

7 0
3 years ago
a fence is to be built to enclose a rectangular area of 240 sq ft. the fence along three sides is to be made of material that co
bixtya [17]

Answer:14400

Step-by-step explanation:

8 0
3 years ago
A ride at a park has room for 8 children to ride at once.
djyliett [7]

Answer:

6

Step-by-step explanation:

45/8=5.625

Since there are .625 children left, we need to add another ride to fill in what's left.

4 0
2 years ago
The slope of the tangent line to the curve x^3y+y^2-x^2=5 at the point (2,1) is
zheka24 [161]

Answer:

-4/5

Step-by-step explanation:

To find the slope of the tangent to the equation at any point we must differentiate the equation.

x^3y+y^2-x^2=5

3x^2y+x^3y'+2yy'-2x=0

Gather terms with y' on one side and terms without on opposing side.

x^3y'+2yy'=2x-3x^2y

Factor left side

y'(x^3+2y)=2x-3x^2y

Divide both sides by (x^3+2y)

y'=(2x-3x^2y)/(x^3+2y)

y' is the slope any tangent to the given equation at point (x,y).

Plug in (2,1):

y'=(2(2)-3(2)^2(1))/((2)^3+2(1))

Simplify:

y'=(4-12)/(8+2)

y'=-8/10

y'=-4/5

5 0
3 years ago
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