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Yanka [14]
4 years ago
11

Pleaseeeeeeeeeeeee helppppppppppppppppp

Mathematics
1 answer:
Fittoniya [83]4 years ago
3 0
You really just have to do 12.4 x 2 = 24.8 because half of 24.8 is 12.4.
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Please help me asap ​
lana [24]

the top question is the second answer and the second question is also the second answer

4 0
3 years ago
Please help me with this​
Tatiana [17]
<h2><u>Given</u> :</h2>

The given equations are :

\longrightarrow15b + 10g = 8640 \:  \:  \:  \:  \:   - (1)

\longrightarrow b + g = 708 \:  \:  \:  \:  \:  \:  - (2)

Let's solve for g in equation (2) :

\longrightarrow b + g = 708

\longrightarrow g = 708 - b \:  \:  \:  \:  \:  - (3)

now, let's plug value of g from equation (3) into equation (1) :

\longrightarrow15b + 10g = 8640

\longrightarrow15b + 10(708 - b) = 8640

\longrightarrow15b - 10b + 7080 = 8640

\longrightarrow5b = 1560

\longrightarrow b = 312

plugging value of b in equation (3) :

\longrightarrow g = 708 - b

\longrightarrow g = 708 - 312

\longrightarrow g =39 6

since " g " represents ground seats, number of ground seats :

=》396

And " b " represents balcony seat, therefore it is equal to :

=》312

\mathrm{ ☠ \: TeeNForeveR \:☠ }

4 0
3 years ago
Two poles are connected by a wire that is also connected to the ground. The first pole is 18 ft tall and the second pole is 24 f
9966 [12]

Answer:

  72 feet from the shorter pole

Step-by-step explanation:

The anchor point that minimizes the total wire length is one that divides the distance between the poles in the same proportion as the pole heights. That is, the two created triangles will be similar.

The shorter pole height as a fraction of the total pole height is ...

  18/(18+24) = 3/7

so the anchor distance from the shorter pole as a fraction of the total distance between poles will be the same:

  d/168 = 3/7

  d = 168·(3/7) = 72

The wire should be anchored 72 feet from the 18 ft pole.

_____

<em>Comment on the problem</em>

This is equivalent to asking, "where do I place a mirror on the ground so I can see the top of the other pole by looking in the mirror from the top of one pole?" Such a question is answered by reflecting one pole across the plane of the ground and drawing a straight line from its image location to the top of the other pole. Where the line intersects the plane of the ground is where the mirror (or anchor point) should be placed. The "similar triangle" description above is essentially the same approach.

__

Alternatively, you can write an equation for the length (L) of the wire as a function of the location of the anchor point:

  L = √(18²+x²) + √(24² +(168-x)²)

and then differentiate with respect to x and find the value that makes the derivative zero. That seems much more complicated and error-prone, but it gives the same answer.

7 0
3 years ago
UDD Question 6 10 pts Solve for x. Round to the nearest tenth (one decimal place). Just type the number, no unit of measurement.
NISA [10]

Answer:

The answer is;

54.4

Step-by-step explanation:

The given parameter are;

Triangle ΔFGH = Right triangle

The length of segment \overline {FH} = 48

The measure of ∠HFG = 28°

The measurement required = The measure of segment \overline {FG} = x

The measure of ∠FHG = 90° angle opposite hypotenuse side of a right triangle

Therefore, ∠FGH = 180° - ∠HFG - ∠FHG = 180° - 90° - 28° = 62°

∠FGH = 62°

By sine rule, we have;

\overline {FH}/(sin ∠FGH) = \overline {FG}/(sin(∠FHG)

By substituting the known values, we have;

48/(sin 62°) = x/(sin(90°)

sin(90°) = 1, therefore, we have;

x/1 = x = 48/(sin 62°) = 54.4 (by rounding the answer to the nearest tenth)

x = 54.4

8 0
3 years ago
The difference of the same side angles of two parallel lines is 35°. Find all angles
Pavel [41]
<h3>Answer:</h3>

All acute angles are 72.5°; all obtuse angles are 107.5°.

<h3>Explanation:</h3>

Angles on the same side of a transversal cutting parallel lines have measures that total 180°. If o and a represent the measures of the obtuse and acute angles, respectively, then we have ...

... o + a = 180

... o - a = 35

Adding these two equations gives ...

... 2o = 215

... 215/2 = o = 107.5 . . . . degrees

Then the other angle is ...

... a = 107.5 - 35 = 72.5 . . . . degrees

_____

All corresponding angles have the same measures. All vertical angles have the same measures. So the 8 angles that arise from the intersection of the transversal with these two parallel lines will have one or the other of these two measures.

3 0
4 years ago
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