Answer:
y = 
Step-by-step explanation:
A line with a slope of zero is a horizontal line parallel to the x- axis.
The equation of a horizontal line is
y = c
where c is the value of the y- coordinates the line passes through.
Here the line passes through (0, ) with y- coordinate , thus
y = ← equation of line
Answer:
Step-by-step explanation:
From Mathematica:<span>DSolve<span>[<span><span>y′</span>[x]=<span><span>(<span>y[x<span>]2</span>−<span>x2</span></span>)</span><span>2xy[x]</span></span>,y[x],x</span>]</span></span><span>{<span><span>{<span>y[x]→−<span><span>−<span>x2</span>+xC[1]</span><span>−−−−−−−−−−</span>√</span></span>}</span>,<span>{<span>y[x]→<span><span>−<span>x2</span>+xC[1]</span><span>−−−−−−−−−−</span>√</span></span>}</span></span>}</span>Take the second solution and square each side:<span>y[x<span>]2</span>=−<span>x2</span>+xC[1]</span>Move the -x^2 from the RHS to the LHS.<span>y[x<span>]2</span>+<span>x2</span>=xC[1]</span>If the same procedure is applied to my answer then the following is the result:<span>y[x<span>]2</span>+<span>x2</span>= 2cx+2C[1]</span><span>where C[1] is zero. I am not sure that their expression is totally correct.</span>
Answer:
Step-by-step explanation:
Let X be the number of persons out of 12 who have RH negative blood.
X is binomial since each person is independent of the other to have Rh negative blood.
n =12
a) What is the probability that exactly 5 of those patients will have Rh negative blood?
P(X=5) =
b) What is the probability that at least 3 of them will have Rh negative blood?
=0.6397
c) What are the expected number and standard deviation of the number of these patients with Rh negative blood?
E(X) = np = 
Var(x) = npq = 
Std dev = 
