Please please help me
1 answer:
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Answer:
x = - 2.5
Step-by-step explanation:
Given that the sketch represents
y = x² + bx + c
The graph crosses the y- axis at (0 , - 14), thus c = - 14
y = x² + bx - 14
Given the graph crosses the x- axis at (2, 0), then
0 = 2² + 2b - 14
0 = 4 + 2b - 14 = 2b - 10 ( add 10 to both sides )
10 = 2b ( divide both sides by 2 )
b = 5
y = x² + 5x - 14 ← represents the graph
let y = 0 , then
x² + 5x - 14 = 0 ← in standard form
(x + 7)(x - 2) = 0 ← in factored form
Equate each factor to zero and solve for x
x + 7 = 0 ⇒ x = - 7
x - 2 = 0 ⇒ x = 2
The x- intercepts are x = - 7 and x = 2
The vertex lies on the axis of symmetry which is midway between the x- intercepts, thus
the x- coordinate of the turning point is =
= - 2.5
Answer:
There will be total 2048 parts of the given paper if James if able to fold the paper eleven times.
The needed function is
Step-by-step explanation:
Let us assume the piece of paper James decides to fold is a SQUARE.
Now, let us assume:
n : the number of times the paper is folded.
y : The number of parts obtained after folds.
Now, if the paper if folded ONCE ⇒ n = 1
Also, when the pap er is folded once, the parts obtained are TWO equal parts.
⇒ for n = 1 , y = 2 ..... (1)
Similarly, if the paper if folded TWICE ⇒ n = 2
Also, when the paper is folded twice, the parts obtained are FOUR equal parts.
⇒ for n = 2 , y = 4 ..... (2)
⇒
Continuing the same way, if the paper is folded SEVEN times ⇒ n = 7
So,
⇒ There are total 128 equal parts.
Lastly, if the paper is folded ELEVEN times ⇒ n = 11
So,
⇒ There are total 2048 equal parts.
Hence, there will be total 2048 parts of the given paper if James if able to fold the paper eleven times.
And the needed function is